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3 years ago

Create and equivalent expression using the distributive property for 5(3s-2)

Mathematics

1 answer:

maxonik [38]3 years ago

3 0

If I read your question right, an equivalent expression would be 15s-10 after distributing the 5.

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11. The completion of a chemical reaction is expressed by the equation y = 300 - 4x - XP, where y is

alina1380 [7]

Answer:

The reaction ca occur at 10 degree Celsius or -14 degree Celsius.

Step-by-step explanation:

We are given the following in the question:

The completion of a chemical reaction is expressed by the equation

$y = 300 - 4x -x^2$

where y is the number of seconds needed to complete the reaction and x is the temperature in degrees Celsius at which the reaction occurs.

We have to find the temperature at which the reaction occurs, if the completion time of reaction is 160 seconds.

Putting y = 160

$160 = 300 - 4x -x^2\\x^2 + 4x - 140 = 0\\x^2 + 14x -10x -140 = 0\\x(x+14)-10(x+14)=0\\(x-10)(x+14) = 0\\(x-10) =0, (x+14) =0\\x = 10, x = -14$

Thus, the reaction ca occur at 10 degree Celsius or -14 degree Celsius.

5 0

3 years ago

The math club is selling gift wrap for a funraiser. They sold 45 rolls of soild wrapping paper at $4 each and rolls of patterned

Lunna [17]

4 * 45 = 180

265 - 180 = 85

85/5 = 17

They sold 17 rolls of patterned wrapping paper.

7 0

3 years ago

Bethany needs to cut a board into 5 equal sections. If the board is 17.55 feet long what will be the length of each section?

AysviL [449]

17.55 divided by 5 is 3.51
So each section is 3.51 feet long

8 0

4 years ago

Read 2 more answers

D. If the speed of a body is increased four times, how will its kinetic energy be affected?

const2013 [10]

Answer:

Step-by-step explanation:

8 0

3 years ago

PLEASE HELPPP!!! THANK YOU SOO MUCH ILY!!!!!!!

MissTica

Answer:

1) Variables = 11a , 4a

Constants = 0

Coefficients = 11 , 4

2) Variables = 3x , 7x

Constants = 6 , -4

Coefficients = 3 , 7 , 6 , -4

3) Variables = -12m , +4m

Constants = -3 , 16

Coefficients = -12 , 4 , -3 , 16

4) Variables = 6k , k

Constants = -4 , -2

Coefficients = 6 , 1 , -4 , -2

5) Variables = -5p , -2p

Constants = 3 , 13

Coefficients = -5 , -2 , 3 , 13

6) Variables = -10r , -r , -6r

Constants = 11

Coefficients = -10 , -1 , -6 , 11

7) Variables = -5n

Constants = 19 , -8 , 14

Coefficients = -5 , 19 , -8 , 14

8) Variables = 13y , -2y

Constants = 18 , -5

Coefficients = 13 , -2 , 18 , -5

9) Variables = 8a , 3a , -7b , -2b

Constants = 1

Coefficients = 8 , 3 , -7 , -2 , 1

10) Variables = 11x , 2x , -4y

Constants = 8

Coefficients = 11 , 2 , -4 , 8

Step-by-step explanation:

8 0

3 years ago