Question

A system of equations is shown below. Solve for x. y = x² - 6x + 4 y = x + 1

Answer 1

The value of x in the given quadratic equations is either -2.7 or -11.3.

What are quadratic equations?

A quadratic equation is a second-degree algebraic equation in x. ax² + bx + c = 0, where a and b are coefficients, x is the variable, and c is the constant term, is the quadratic equation in its simplest form.

Given first equation, y = x²- 6x + 4 second equation, y = x +1

Put the value of y in the first equation to get

x + 1 = x² - 6x + 4

Solving this equation

x² - 7x + 3 = 0

Using quadratic formula,

x = - b ± $\frac{\sqrt{(b^{2}- 4ac)}}{2a}$

x = - 7 ±  $\frac{\sqrt{(-7)^{2}- 4(3)}}{2}$

x = - 7 ± 4.3

Therefore in the given quadratic equations, the value of x can be either -2.7 or -11.3

For more information on quadratic equations, visit:

brainly.com/question/1863222

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