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posledela
3 years ago
11

Given that (x,y) = (5,15) find tan Ø. A. 3 B. 1/3 C. 5 D. 1/5

Mathematics
1 answer:
lesantik [10]3 years ago
7 0
This value is in the positive quadrant meaning that all values remain positive. To answer this problem you must have an understanding of trig ratios being that tangent is opposite/adjacent. When you plot the points and draw a triangle using the origin of the point, you find that the adjacent value is 5 and opposite value is 15
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Find two positive numbers whose difference is 30 and whose product is 2584.
kvasek [131]

Answer:

38 and 68.

Step-by-step explanation:

Let x be the smaller one of the two number.

x must be a positive integer. The other number would be (x + 30).

The question states that the product of the two numbers is 2584. In other words:

x\, (x + 30) = 2584.

Rearrange this equation and solve for x:

x^{2} + 30\, x - 2584 = 0.

The first root of this quadratic equation would be:

\begin{aligned}x_{1} &= \frac{(-30) + \sqrt{30^{2} - 4 \times (-2584)}}{2} \\ &= \frac{(-30) + \sqrt{900 + 10336}}{2} \\ &= \frac{(-30) + \sqrt{11236}}{2} \\ &= \frac{(-30)}{2} + \sqrt{\frac{11236}{2^{2}}} \\ &= (-15) + \sqrt{2809} \\ &= (-15) + 53 \\ &= 38 \end{aligned}.

Similarly, the second root of this quadratic equation would be:

\begin{aligned}x_{1} &= \frac{(-30) - \sqrt{30^{2} - 4 \times (-2584)}}{2} \\ &= (-15) - 53 \\ &= -68\end{aligned}.

Since the question requires that both numbers should be positive, x > 0. Therefore, only x = 38 is valid.

Hence, the two numbers would be 38 and (38 + 30), which is 68.

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Step-by-step explanation:

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