Let x- intercept represents time
Let y-intercept represents population
Let 1990 represent initial year
Points are (0,14.2)(10,12.4)
slope m= 
= 
General linear equation
y= mx+b --------------(i)
here m is slope and b is intercept
plug the 1st point in equation
14.2= -0.018(0) + b
b=14.2
y= 0.018x + 14.2
replace y with p(t) and x with t
p(t) = -0.018t + 14.2
Answer:
Step-by-step explanation:
36 = 6* 6 = 2* 3 * 2* 3 = 2*2*3*3
180 = 2 * 2 * 3 * 3 * 5 = 2 * 2 * 3*3*5

Factors that are common will be cancelled
Answer:
y=5^x
5^15= 30517578125 people
Step-by-step explanation:
x=# of cycles= 15 cycles
y= #of people recruited = what we're figuring out
Plug in 15 for x in the equation y=5^x
y= 5^15= 30517578125 people
Answer:
x^2 + 8x + 16
Step-by-step explanation:
(x + 4) (x+ 4) multiply x by x and x by 4.
x^2 + 4x
Then multiply 4 by x and 4 by 4.
4x + 16
Then combine like terms.
x^2 + 4x + 4x +16
x^2 + 8x + 16
Answer:
<h2>B. The amount of fuel used was lowest at speeds around 60km/h.</h2>
Step-by-step explanation:
The decreasing part is from (20,13) to (60,6), which gives an average rate of

Then, we have an increasing part from (60,6) to (120,10), which gives an average rate of

Basically, at 60 km/h the fuel used was 6 liters per 100 kilometers. Notice that the other velocities make the car to use more liters per kilometers.
Therefore, the amount of fuel used was lowest at speeds around 60 km/h.