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Elena-2011 [213]
3 years ago
11

HELP

Mathematics
1 answer:
Ann [662]3 years ago
5 0

Answer:

\frac{x^2}{7}+1 \text{ is a polynomial;}\\-2x^3+2x+4 \text{ is a polynomial;}\\x^{-3}+4x \text{ is not a polynomial;}\\\text{and }6x-x^3+4x^2 \text{ is a polynomial.}

Step-by-step explanation:

A polynomial is the sum or difference of one or more monomials.  A monomial is a constant, a variable, or the product of constants and variables.  It does not include negative exponents.

The first choice is a polynomial because the only terms are variables with positive exponents and constants.

The second choice is a polynomial because the only terms are variables with positive exponents and constants.

The third choice is not a polynomial because the first term has a negative exponent.

The fourth choice is a polynomial because the only terms are variables with positive exponents and constants.

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Which of the following is true for the relation f(x) = x2 + 8? Only the inverse is a function. Both the equation and its inverse
Alchen [17]

<u>ANSWER</u>

Only the equation is a function

<u>EXPLANATION</u>

f(x)=x^2+8 is graphed above with its inverse f^{-1}(x)=\pm \sqrt{x-8}.


We perform the vertical line test for both the equation and its inverse.


The equation f(x)=x^2+8 passed the vertical line hence it is a function.

However, f^{-1}(x)=\pm \sqrt{x-8} failed the vertical line test, hence it is not a function.


3 0
3 years ago
Suppose f and g are continuous functions such that g(2) = 6 and lim x → 2 [3f(x) + f(x)g(x)] = 36. find f(2).
True [87]

Answer: f(2) = 4

Step-by-step explanation:

F(x) and g(x) are said to be continuous functions

Lim x=2 [3f(x) + f(x)g(x)] = 36

g(x) = 2

Limit x=2

[3f(2) + f(2)g(2)] = 36

[3f(2) + f(2) . 6] = 36

[3f(2) + 6f(2)] = 36

9f(2) = 36

Divide both sides by 9

f(2) = 36/9

f(2) = 4

7 0
3 years ago
What is a​ population?. a population is the set containing all the people or objects whose properties are to be described and an
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7 0
3 years ago
Hi. Please I need help with these questions.
ElenaW [278]

Answer:

Q 12 roots of the equation

2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\

∝ = \frac{\sqrt{10} }{2}

β = -\frac{\sqrt{10} }{2}

no matter if u oppose the root

(i) 2(\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2} )^{2}+2(\frac{\sqrt{10} }{2} )^{2}(-\frac{\sqrt{10} }{2})+2(

(ii)((\frac{\sqrt{10} }{2})^{2} - 3 (\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2}) + ((-\frac{\sqrt{10} }{2})^{2}) = \frac{25}{2}

Q 13  roots of equation

4x^{2} -3x-4=0\\\alpha = -0.693\\\beta = 1.443

the roots of the second equation are

x1 = 1/3(-0.693) = -0.231

x2 = 1/3(1.443) = 0.481

the equation is

(x+0.231)(x-0.481)=0

x^{2}-\frac{1}{4} x-\frac{1}{9}

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3 years ago
Encuentra la medida del segmento AB conociendo que : DE//BC medida del ángulo EDA=90 grados ,AD=2cm,DE=3cm y BC=18cm
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Hii its charli damelio
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