Question

From a rope 11m long two pieces of lengths 13/5m and 33/10m are cut off. What is the length the remaining rope?

Answer 1

Answer:

$\frac{51}{10}$m

Step-by-step explanation:

Given parameters:

  Length of rope = 11m

 First length cut off = $\frac{13}{5}$m

  Second length cut off = $\frac{33}{10}$m

Unknown:

Remaining length  = ?

Solution:

Let us find the total length cut off first;

       =     $\frac{13}{5}$m   +  $\frac{33}{10}$m

         = $\frac{26 + 33}{10}$

          = $\frac{59}{10}$m

So,

 Remaining length  = 11 -  $\frac{59}{10}$

                                 = $\frac{110 - 59}{10}$  

                                 = $\frac{51}{10}$m