4 years ago

Use log_2 7 is about 2.8074 and log_2 5 is about 2.3219 to approximate log_2 175?

Mathematics

2 answers:

Anton [14]4 years ago

5 0

Answer:

it would be log 1/2 5

Step-by-step explanation:

Stella [2.4K]4 years ago

4 0

Remembe
$log_ax+log_ay=log_a(xy)$

so
notice
7*5*5=175

so we want to multiply them
add

$log_27+log_25+log_25=log_2175$ =
(2.8074)(2.3219)(2.3219)=15.135309933114

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