Question

Use log_2 7 is about 2.8074 and log_2 5 is about 2.3219 to approximate log_2 175?

Answer 1

Answer:

it would be log 1/2 5

Step-by-step explanation:

Answer 2

Remembe
$log_ax+log_ay=log_a(xy)$


so
notice
7*5*5=175

so we want to multiply them
add

$log_27+log_25+log_25=log_2175$=
(2.8074)(2.3219)(2.3219)=15.135309933114