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4 years ago

Are relstioships that have an initial fee proportional or non-proportionial?

1 answer:

3 0

They are non-proportional because the y-value doesn't depend on what the x-value is and the x-value only. Hope this helps!

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What is -4+0+y, When y=16

BlackZzzverrR [31]

$\large \mathfrak{Solution : }$

let's plug in the value of y :

-4 + 0 + y

-4 + 16

8 0

3 years ago

Read 2 more answers

Every other weekend,Bronwyn Brother Danial mows the lawn. He can mow 15,000ft2 in 3/4 hour. who mows the lawn in less time? plea

ivann1987 [24]

Answer:

you left something out but you need to put it in a better understanding

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Three forces act on a hook. Determine the magnitude of the resultant of the force.

Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

$\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y$

$\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y$

$\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y$

The resultant force is the sum of these vectors,

$\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y$

and has magnitude

$|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N$

The closest answer is D.

5 0

3 years ago

According to an NRF survey conducted by BIGresearch, the average family spends about $237 on electronics (computers, cell phones

schepotkina [342]

Answer:

7.64% probability that they spend less than $160 on back-to-college electronics

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 237, \sigma = 54$