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3 years ago

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Andrew walks 3/4 mile in 10 minutes. Jill walked 4/5 mile in 15 minutes. What was the difference in their speeds, in miles per h

our?

1 answer:

andreyandreev [35.5K]3 years ago

3 0

The difference of their speeds is 1.3 mph because Andrew was walking 4.5 mph and Jill was walking 3.2mph.

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A data set consists of these points: (2, 4), (4,7), (5, 12). malinda found the

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The complete question is

"A data set consists of the following data points: (2,4),(4,7), (5, 12)

The line of best fit has the equation y = 2.5x - 1.5. What does this equation predict for a value of x = 7?

O A. 16

O B. 19

O C. 20.5

O D. 175

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a. no. both a and b are incorrect.

b. no. the value for b is incorrect.

c. no. the value for a is incorrect.

d. yes. this is the correct equation."

The equation predict for a value of x = 7 in equation y = 2.5x – 1.5 is (x, y) = (3, 16). Option B is correct.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

"A data set consists of the following data points: (2,4),(4,7), (5, 12)

y = 2.5x - 1.5

Puy x = 7

y = 2.5(7) - 1.5

y = 17.5 - 1.5

y = 16

The equation predict for a value of x = 7 in equation y = 2.5x – 1.5 is (x, y) = (3, 16). Option B is correct.

Learn more about equations here;

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Step-by-step explanation:

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A function which has a constant difference per interval is?

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Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

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2 years ago