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s2008m [1.1K]
3 years ago
15

Find the constant of variation k for the direct variation x -1 0 2 5 f(x) 2 0 -4 -10

Mathematics
1 answer:
Fofino [41]3 years ago
8 0

Answer:

k = -2

Step-by-step explanation:

x     -1   0   2     5

f(x)  2   0  -4  -10

ƒ(x) = kx

Substitute a pair of values for x and ƒ(x)

-10 = k×5

Divide each side by 5

k = -2

The constant of variation k = -2.

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Answer:

x = 180

Step-by-step explanation:

Solve the value of x :

0.25x + 7 = \frac{1}{3}x - 8

-Combine \frac{1}{3}x and 0.25x by subtracting 0.25x by \frac{1}{3}x :

0.25x - \frac{1}{3}x  + 7 = \frac{1}{3}x - \frac{1}{3}x  - 8

-\frac{1}{12}x + 7 = -8

-Subtract 7 on both sides:

-\frac{1}{12}x + 7 - 7 = -8 - 7

-\frac{1}{12}x = -15

-Multiply both sides by -12, the reciprocal of -\frac{1}{12} :

\frac{-\frac{1}{12}x}{-\frac{1}{12}} = \frac{-15}{-\frac{1}{12}}

x = -15 (-12)

x = 180

Therefore, the value of x is 180.

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3 years ago
Xander and Pedro are at an ice cream social.for every scoop of ice cream,Xander uses 1/8 cup of fruit topping.Pedro uses one mor
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Step-by-step explanation:

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3 years ago
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What is the product 1/4 times 3 ? Use the visual model to answer the question?
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Which of the following best describes the graphs below?​
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37% dextrose solution (37 mg per 100ml of solution) is given iv. Suppose a total of 3.81 liters is given over a 15 hour period.
sashaice [31]

Answer:

During 15 hour period, 1409.7 mg of dextrose will be delivered.

The flow rate of dextrose per hour will be 93.98 mg/hour.

Step-by-step explanation:

If a total of 3.81 liters of the solution is given over a 15 hour period.

Now, 1 liter is equivalent to 1000 ml

So, a total of 3810 ml of the solution is given over a 15 hour period.

If 100 ml of solution contains 37 mg of dextrose, then 3810 ml of the solution will contain \frac{37 \times 3810}{100} = 1409.7 mg of dextrose.

So, during the 15 hour period, 1409.7 mg of dextrose will be delivered.

The flow rate of dextrose per hour will be \frac{1409.7}{15} = 93.98 mg/hour. (Answer)

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