Answer:
Step-by-step explanation:
The average number is given by :
[m + (m - 1200) + (m - 1200)(1.30 ] / 3 =
[ 2m + 1.30m - 1200 - 1560] / 3 =
[3.3m - 2760] / 3 =
[1.1 m - 920 ]
Answer:
The three consecutive POSITIVE ODD integers are: 3, 5 and 7
Step-by-step explanation:
If x is an integer, then there consecutive positive odd integers are:
x , x + 2, x + 4 are three consecutive integers.
Where
First integer, a = x
Second integer, b = x + 2
Third integer, c = x + 4
We are told to:
Find three consecutive POSITIVE ODD integers such that when you multiply the first and third the result is nine less than six times the second integer.
Hence, this is represented as:
a × c = 6(b) - 9
Where
a = x
b = x + 2
c = x + 4
x (x + 4 ) = 6(x + 2) - 9
x ² + 4x = 6x + 12 - 9
x² +4x - 6x - 12 + 9= 0
x² - 2x - 3 = 0
Factorising
x² +x - 3x - 3 = 0
x (x + 1) -3(x + 1) = 0
(x - 3) (x + 1) = 0
x - 3 = 0
x = 3
x + 1 = 0
x = -1
Since, x cannot be negative for this question, x = 3
First integer, a = x = 3
Solving for:
Second integer, b = x + 2
b = 3 + 2 = 5
Solving for :
Third integer, c = x + 4
c = 3 + 4 = 7
Therefore, the three consecutive POSITIVE ODD integers are: 3, 5 and 7
The photo show how to solve the equation. Also you can use calculator to solve the problem. The easiest way of doing this is using a scientific calculator then use shift solve method for the ans
To solve this, you must follow PEMDAS. First, solve the parenthesis. Because a negative times a positive equals a negative, the product of the fractions is -1/6. Then multiply that by 12. That equals -12/6. This can be simplified down to -2.
If you need more help, comment below and I will do my best.