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Dennis_Churaev [7]
3 years ago
14

Why is system software dependent on underlying machine architecture?

Computers and Technology
1 answer:
IRINA_888 [86]3 years ago
5 0
Once a source code is compiled to machine code, it becomes specific to the platform targeted, to the machine architecture. So, this is the reason why the <span>system software is dependent on the underlying machine architecture. It is t</span><span>he reason why you cannot run a Linux program on Windows , for example. </span>Source code can be compiled to target different architectures and executable formats. <span>
T</span>
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The hard drive should have saved his data.
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Read 2 more answers
. What is the relationship between frequency, wavelength and speed of a wave?
jeka94

Answer:

vw = fλ

Explanation:

Sound, like all waves, travels at a certain speed and has the properties of frequency and wavelength. You can observe direct evidence of the speed of sound while watching a fireworks display. The flash of an explosion is seen well before its sound is heard, implying both that sound travels at a finite speed and that it is much slower than light. You can also directly sense the frequency of a sound. Perception of frequency is called pitch. The wavelength of sound is not directly sensed, but indirect evidence is found in the correlation of the size of musical instruments with their pitch. Small instruments, such as a piccolo, typically make high-pitch sounds, while large instruments, such as a tuba, typically make low-pitch sounds. High pitch means small wavelength, and the size of a musical instrument is directly related to the wavelengths of sound it produces. So a small instrument creates short-wavelength sounds. Similar arguments hold that a large instrument creates long-wavelength sounds.

The relationship of the speed of sound, its frequency, and wavelength is the same as for all waves: vw = fλ, where vw is the speed of sound, f is its frequency, and λ is its wavelength. The wavelength of a sound is the distance between adjacent identical parts of a wave—for example, between adjacent compressions as illustrated in Figure 2. The frequency is the same as that of the source and is the number of waves that pass a point per unit time.

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3 years ago
An instance variable name of type String, initialized to the empty String. An instance variable score of type int, initialized t
timofeeve [1]

Answer:

public class Class {

   private String name ="";

   private int score = 0;

   //Method SetName

   public void setName(String newName){

       name = newName;

   }

//Method SetScore

   public void setScore(int newScore){

       score = newScore;

   }

//Method GetName

   public String getName() {

       return name;

   }

//Method GetScore

   public int getScore() {

       return score;

   }

}

Explanation:

  • The class called Class is implemented in Java programming language
  • It has two fields (instance variables name and score)
  • Methods for setting the values of variables (mutator methods) or setters
  • Methods for getting the values of the variables (accessor methods) getters
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A domain name points to a specific internet address known as a? A. Domain name B. User name C. URL D. IP address
hodyreva [135]
C, URL since the other options aren’t addresses at all
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4 years ago
Write a function called has_duplicates that takes a string parameter and returns True if the string has any repeated characters.
vichka [17]

Answer:

Explanation:

The python code for the question is attached in the image below.

The objective here is to write a code in python with a function called has_duplicates that takes a string parameter and returns True if the string has any repeated characters. Otherwise, it should return False.

SEE BELOW FOR THE CODE.

alphabet = "abcdefghijklmnopqrstuvwxyz"

test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]

test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]

def histogram(s):

   d = dict()

   for c in s:

       if c not in d:

           d[c]=1

       else:

           d[c] += 1

   return d

def has_duplicates():

   for string in test_dups:

       dictionary=histogram(string)

       duplicates=False

       for ch in dictionary.keys():

           if dictionary[ch] > 1:

               duplicates=True

               break

       if duplicates==True:

           print(string,"has duplicates")

       else:

           print(string,"has no duplicates")

def missing_letters(string):

   answer=""

   for ch in alphabet:

       if ch not in string:

           answer=answer+ch

   return answer

print("__________________________________________")

print(" Calling has_duplicates() function")

print("__________________________________________")

has_duplicates()

print("\n______________________________________________")

print("Calling missing_letters() function in for loop")

print("______________________________________________")

for i in test_miss:

   answer=missing_letters(i)

   if len(answer)>=1:

       print(i,"is missing letters",answer)

   else:

       print(i,"uses all the letters")

3 0
3 years ago
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