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Crank
3 years ago
8

What is factored form of the expression 16st+15t ​

Mathematics
2 answers:
svet-max [94.6K]3 years ago
8 0

Answer:

t(16s+15)

Step-by-step explanation:

The highest common factor of 16st+15t is t.

t(16s) + t(15)

Factor.

t(16s+15)

storchak [24]3 years ago
6 0

Answer:

t ( 16s+15)

Step-by-step explanation:

=> 16st + 15t

Taking t common

=> t ( 16s+15)

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(Edge comparing data sets quiz) what can be made between the two sets of data in the table?​
telo118 [61]

Answer: The 1st one I think.

5 0
3 years ago
How can you add 3over 10 and 2over5
otez555 [7]

Answer:

7/10

Step-by-step explanation:

3/10+2/5

You have to make like denominators

So you multiply 2/5 by 2 since 1/ is the common denominator.

Then you add them

Hope this helped

6 0
3 years ago
Read 2 more answers
1) Two similar rectangles are shown. Which statement is true? A) The area of rectangle B is 1 3 the area of rectangle A. B) The
Arturiano [62]

Answer: C

Step-by-step explanation:

We know the scale factor is 6/2=3.

A) False. The ratio of the side lengths, not the areas, is 1 to 3.

B) False. Rectangle B is larger than Rectangle A.

C) The square of the ratio of the side lengths is the ratio of the areas.

D) False. The ratio of the side lengths, not the areas, is 1 to 3.

3 0
2 years ago
Find sin 2x, cos 2x, and tan 2x from the given information.<br> cscx=4,tanx&lt;0.
lutik1710 [3]

Answer:

Step-by-step explanation:

Given the expression cosec (x) = 4 and tan(x)< 0

since cosec x = 1/sinx

1/sinx = 4

sinx = 1/4

From SOH, CAH TOA

sinθ = opposite/hypotenuse

from sinx = 1/4

opposite = 1 and hypotenuse = 4

to get the adjacent, we will use the Pythagoras theorem

adj² = 4²-1²

adj² = 16-1

adj ²= 15

adj = √15

cosx = adj/hyp = √15/4

tanx = opposite/adjacent = 1/√15

since tan < 0, then tanx = -1/√15

From double angle formula;

sin2x = 2sinxcosx

sin2x = 2(1/4)(√15/4)

sin2x = 2√15/16

sin2x = √15/8

for cos2x;

cos2x = 1-2sin²x

cos2x = 1-2(1/4)²

cos2x = 1-2(1/16)

cos2x= 1-1/8

cos2x = 7/8

for tan2x;

tan2x  = tanx + tanx/1-tan²x

tan2x = 2tanx/1-tan²x

tan2x = 2(-1/√15)/1-(-1/√15)²

tan2x = (-2/√15)/(1-1/15)

tan2x = (-2/√15)/(14/15)

tan2x = -2/√15 * 15/14

tan2x = -30/14√15

tan2x = -30/7√15

rationalize

tan2x =  -30/7√15 * √15/√15

tan2x =  -30√15/7*15

tan2x =  -2√15/7

5 0
3 years ago
Find the sum of the first 6 terms of 3 - 6 + 12 + …
Natalka [10]

Answer:

S_6 = -63

Step-by-step explanation:

The sequence above is a geometric sequence.

The common ratio (r) = \frac{-6}{3} = \frac{12}{-6} = -2

The common ratio < 1, therefore, the formula for the sum of nth terms of the sequence would be: S_n = \frac{a_1(1 - r^n)}{1 - r}

a1 = 3

r = -2

n = 6

Plug in the values into the formula

S_6 = \frac{3(1 - (-2^6)}{1 - (-2)}

S_6 = \frac{3(1 - (64)}{1 + 2}

S_6 = \frac{3(-63)}{3}

S_6 = -63

6 0
3 years ago
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