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Temka [501]
2 years ago
15

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Mathematics
1 answer:
Natalka [10]2 years ago
5 0

Answer:  B. ( -∞ , 0)   and   C. (1, 2)

<u>Step-by-step explanation:</u>

The y-value is increasing between x = -∞ and x = 0.

The y-value is decreasing between x = 0 and x = 1.

The y-value is increasing between x = 1 and x = 2.

The y-value is decreasing between x = 2 and x = +∞


So, the y-value is increasing at ( -∞ , 0) ∪ (1, 2)

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Let f:X → Y, where X and Y are the set of all real numbers, and x and h are real numbers.
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Step-by-step explanation:

HI!

a)

an example of this kind of function is f(x) = x^2 because

f(x+h) = (x+h)^2 = x^2 + h^2 + 2 xh = f(x) + f(h) + 2xh

teherfore

f(x+h) ≠ f(x) + f(h)

other example is f(x) = x^n with n a whole number different than one

e.g.

f(x)=x^3

f(x+h) = (x+h)^3 = x^3 + h^3 + 3(x^2 h + x h^2) ≠ x^3 + h^3 = f(x) + f(h)

b)

f(x) = x is a function that actually behaves as indicated

f(x+h) = x + h = f(x) + f(h)

others examples of this kind of fucntion are given by multiplying x by any number:

f(x) = ax;    f(x+h) = a(x+h) = ax + ah = f(x) + f(h)

c)

Any pair of numbers will make f(x+h) = f(x) + f(h), as mentioned in the previous section

lest consider 10 and 5

f(10+5) = 2 *(10+5) = 2*15 = 30

f(10) = 2*10 = 20

f(5) = 2*5 = 10

f(10) + f(5) = 20+10 = 30 = f(10+5)

5 0
3 years ago
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