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4 years ago

What multiplies to -10000 and adds up to 0?

Mathematics

2 answers:

aleksley [76]4 years ago

5 0

1
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Lapatulllka [165]4 years ago

4 0

It is 0 because if you multiply 0 to any number it is 0

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Identify the range of the function shown in the graph.

Kitty [74]

Answer: The answer is all real numbers

Step-by-step explanation:

This is the answer because the line goes on infinitely and will pass through all of the numbers (negative, positive). Its not y $\geq \\$ 0 because it passes through 0 when the line goes through x (side to side) axis.

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3 years ago

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jek_recluse [69]

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3 years ago

A drop of water from a special dropper is 3 ml. How many liters is this? 30 0.3 0.03 0.003

lesantik [10]

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3 years ago

Read 2 more answers

Write 77.5% as a fraction or mixed number in simplest form.

Delicious77 [7]

Answer:

The answer is $77\frac{1}{2}$ .

Step-by-step explanation:

Given:

77.5%.

Now, to write as a fraction or mixed number in simplest form.

77.5%

So, we divide by 10 by removing decimal as decimal is at tenth place.

= $\frac{775}{10}$

So, simplifying it:

$=\frac{155}{2}$

Now, we change into mixed fraction:

$=77\frac{1}{2}$

Therefore, the answer is $77\frac{1}{2}$ .

7 0

3 years ago

HELP ME PLEASE

solmaris [256]

Answer:

The initial mass of the sample was 16 mg.

The mass after 5 weeks will be about 0.0372 mg.

Step-by-step explanation:

We can write an exponential function to model the situation.

Let the initial amount be A. The standard exponential function is given by:

$P(t)=A(r)^t$

Where r is the rate of growth/decay.

Since the half-life of Palladium-100 is four days, r = 1/2. We will also substitute t/4 for t to to represent one cycle every four days. Therefore:

$\displaystyle P(t)=A\Big(\frac{1}{2}\Big)^{t/4}$

After 12 days, a sample of Palladium-100 has been reduced to a mass of two milligrams.

Therefore, when x = 12, P(x) = 2. By substitution:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^{12/4}$

Solve for A. Simplify:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^3$

Simplify:

$\displaystyle 2=A\Big(\frac{1}{8}\Big)$

Thus, the initial mass of the sample was:

$A=16\text{ mg}$

5 weeks is equivalent to 35 days. Therefore, we can find P(35):

$\displaystyle P(35)=16\Big(\frac{1}{2}\Big)^{35/4}\approx0.0372\text{ mg}$

About 0.0372 mg will be left of the original 16 mg sample after 5 weeks.

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3 years ago