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Alex73 [517]
2 years ago
14

Find the factors of f(x) given that x = 5 is a zero.

Mathematics
1 answer:
77julia77 [94]2 years ago
8 0
  • If x = 5 is a zero of the given polynomial, then,
  • (x - 5) is a factor of the polynomial. [Since, x = 5 or, x - 5 = 0]
  • Now, divide the polynomial with (x - 5) using long division method. (See the picture)
  • We get (x^2 - x - 6) as the quotient.
  • Now, factorise the above polynomial:
  • (x^2 - x - 6)
  • = (x^2 - 3x + 2x - 6)
  • = x(x - 3) + 2(x - 3)
  • = (x - 3)(x + 2)
  • Therefore, x^3 − 6x^2 − x + 30 = (x − 5)(x − 3)(x + 2)

<u>Answer</u><u>:</u>

<u>B.</u><u>(x − 5)(x − 3)(x + 2)</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

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12345 [234]
X^2-7=0
Add 7 to both sides.
x^2=7
Find the sqr root of 7.
It's about 2.6
5 0
3 years ago
Alaska has a coastline of about 6.64 thousand miles. Florida has about 1.35 thousand miles of coastline. How many times more mil
victus00 [196]
All you need to do is divide 6.64 and 1.35. you would get 4.91851852. But, you need to round to the nearest tenth so it would actually be 4.9.
3 0
3 years ago
1+4x/6=3.5<br> What is x
bagirrra123 [75]

Answer:

x=3+3/4

Step-by-step explanation:

1+4x/6=3.5

We move all terms to the left:

1+4x/6-(3.5)=0

We add all the numbers together, and all the variables

4x/6-2.5=0

We multiply all the terms by the denominator

4x-(2.5)*6=0

We add all the numbers together, and all the variables

4x-15=0

We move all terms containing x to the left, all other terms to the right

4x=15

x=15/4

x=3+3/4

3 0
3 years ago
Lcm of (x-2)(x+3) and 10(x+3)^2
Arte-miy333 [17]
Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:

(x - 2)(x + 3)          10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²

Answer: LCM is 10(x - 2)(x + 3)²


8 0
3 years ago
Help with this question please!
Anton [14]

∠1 and ∠2 are alternate exterior angles where transversal BE crosses parallel lines AC and DF, therefore they are equal. ∠2 and ∠3 are opposite angles of a parallelogram, therefore they are equal.

... ∠1 = ∠2

... 3x -5 = 2x +15 . . . . substitute the given values

... x = 20 . . . . . . . . . . . add 5-2x

The measures of angles 1, 2, and 3 are 2·20+15 = 55 . . . degrees.

5 0
3 years ago
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