X^2-7=0
Add 7 to both sides.
x^2=7
Find the sqr root of 7.
It's about 2.6
All you need to do is divide 6.64 and 1.35. you would get 4.91851852. But, you need to round to the nearest tenth so it would actually be 4.9.
Answer:
x=3+3/4
Step-by-step explanation:
1+4x/6=3.5
We move all terms to the left:
1+4x/6-(3.5)=0
We add all the numbers together, and all the variables
4x/6-2.5=0
We multiply all the terms by the denominator
4x-(2.5)*6=0
We add all the numbers together, and all the variables
4x-15=0
We move all terms containing x to the left, all other terms to the right
4x=15
x=15/4
x=3+3/4
Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:
(x - 2)(x + 3) 10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²
Answer: LCM is 10(x - 2)(x + 3)²
∠1 and ∠2 are alternate exterior angles where transversal BE crosses parallel lines AC and DF, therefore they are equal. ∠2 and ∠3 are opposite angles of a parallelogram, therefore they are equal.
... ∠1 = ∠2
... 3x -5 = 2x +15 . . . . substitute the given values
... x = 20 . . . . . . . . . . . add 5-2x
The measures of angles 1, 2, and 3 are 2·20+15 = 55 . . . degrees.