Find the factors of f(x) given that x = 5 is a zero.
1 answer:
- If x = 5 is a zero of the given polynomial, then,
- (x - 5) is a factor of the polynomial. [Since, x = 5 or, x - 5 = 0]
- Now, divide the polynomial with (x - 5) using long division method. (See the picture)
- We get (x^2 - x - 6) as the quotient.
- Now, factorise the above polynomial:
- (x^2 - x - 6)
- = (x^2 - 3x + 2x - 6)
- = x(x - 3) + 2(x - 3)
- = (x - 3)(x + 2)
- Therefore, x^3 − 6x^2 − x + 30 = (x − 5)(x − 3)(x + 2)
<u>Answer</u><u>:</u>
<u>B.</u><u>(x − 5)(x − 3)(x + 2)</u>
Hope you could get an idea from here.
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Answer:
Step-by-step explanation:
You don't need to memorize all of the square roots. Looking at each square root, find a number close to it that you know -- The square root of five is close to the square root of four, which is 2. The square root of 28 is close to the square root of 25, which is 5. 28 is a slightly bigger than 25, so the square root will be slightly greater than 5.