Find the factors of f(x) given that x = 5 is a zero.
1 answer:
- If x = 5 is a zero of the given polynomial, then,
- (x - 5) is a factor of the polynomial. [Since, x = 5 or, x - 5 = 0]
- Now, divide the polynomial with (x - 5) using long division method. (See the picture)
- We get (x^2 - x - 6) as the quotient.
- Now, factorise the above polynomial:
- (x^2 - x - 6)
- = (x^2 - 3x + 2x - 6)
- = x(x - 3) + 2(x - 3)
- = (x - 3)(x + 2)
- Therefore, x^3 − 6x^2 − x + 30 = (x − 5)(x − 3)(x + 2)
<u>Answer</u><u>:</u>
<u>B.</u><u>(x − 5)(x − 3)(x + 2)</u>
Hope you could get an idea from here.
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Answer:
Step-by-step explanation:
The complete question is
Water flows into a tank according to the rate F(t)= (t+6)/(1+t), and at the same time empties out at the rate E(t)= (ln(t+2))/(t+1), with both F(t) and E(t) measured in gallons per minute. How much water, to the nearest galllon, is in the tank at time t=10 minutes.
Let C(t) be the amount of water in the tank at time t. We now that the rate of change of the tank is given by
Unfortunately, the integral cannot be expressed using fundamental functions. So, the problem cannot have an specific function (if you are willing to know the complete answer, the integral of this function uses the polylogarithm function with n=2).
Since you want the exact amount of water at time, you need to give C a value, that is, you need to know an initial condition for the problem. This means, you need to know the amount of water in the tank at time 0