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lukranit [14]
3 years ago
5

How to find the volume of a cone with its base in algebra​

Mathematics
1 answer:
marin [14]3 years ago
7 0

Answer:

V=pi r² h/3

Step-by-step explanation:

V=volume

R=radius

H=height

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What is the solution to the following system?​
katrin2010 [14]

Answer: C. x=0, y=2, z=5

Step-by-step explanation:

you can just plug in the numbers and see which ones work

7 0
3 years ago
Lori is three times as old as Michelle. In five years Michelle's age will be one half of Lori's age. How old are Lori and Michel
AURORKA [14]

Answer:

Lori's age is 15 years old and Michelle's age is 5 years old now

Step-by-step explanation:

Let

x-----> Lori's age

y ----> Michelle's age

we know that

x=3y-----> equation A

(y+5)=\frac{1}{2}(x+5) ----> equation B

substitute equation A in equation B and solve for y

(y+5)=\frac{1}{2}(3y+5)

2y+10=(3y+5)

3y-2y=10-5

y=5

Find the value of x

x=3(5)=15

therefore

Lori's age is 15 years old and Michelle's age is 5 years old now

7 0
3 years ago
How many times does 2 go into 64
Ghella [55]
The corect answer is 32
5 0
3 years ago
Read 2 more answers
Kite E F G H is inscribed in a rectangle. Points F and H are midpoints of sides of the rectangle, and creates a side length of x
Hoochie [10]

Answer:

5 units

Step-by-step explanation:

Let point O be the point of intersection of the kite diagonals.

|OF| = 2, |OH| = 5

|FH| = |OF| + |OH| = 2 + 5 = 7

FH and EG are the diagonals of the kite. Hence the area of thee kite is:

Area of kite EFGH = (FH * EG) / 2

Substituting:

35 = (7 * |EG|) / 2

|EG| * 7 = 70

|EG| = 10 units

The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units

x = |GO| = |EO| = 5 units

7 0
3 years ago
Read 2 more answers
How do you do this question?
daser333 [38]

Answer:

B. 1/2

Step-by-step explanation:

\lim_{z \to 0} \frac{g(z)e^{-z}-3}{z^{2}-2z}

If we plug in 0 for z, we get 0/0.  Apply l'Hopital's rule.

\lim_{z \to 0} \frac{-g(z)e^{-z}+g'(z)e^{-z}}{2z-2}

Now when we plug in 0 for z, we get:

\frac{-g(0)e^{0}+g'(0)e^{0}}{2(0)-2}\\\frac{-g(0)+g'(0)}{-2}\\\frac{-3+2}{-2}\\\frac{1}{2}

4 0
2 years ago
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