The standard form for the equation of a circle is :
<span><span><span> (x−h)^</span>2</span>+<span><span>(y−k)^</span>2</span>=<span>r2</span></span><span> ----------- EQ(1)
</span><span> where </span><span>handk</span><span> are the </span><span>x and y</span><span> coordinates of the center of the circle and </span>r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (−10,1)and(−8,5) is :
((−10+(−8))/2,(1+5)/2)=(−9,3)
So the point (−9,3) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(−10−(−9))^2+(1−3)^2=1+4=5
⇒r=√5
Subtituting h=−9, k=3 and r=√5 into EQ(1) gives :
(x+9)^2+(y−3)^2=5
9514 1404 393
Answer:
see attached for a graph
x = 0.5 when y = 1
Step-by-step explanation:
The graph has a y-intercept of -1, which is halfway between 0 and -2. It goes up 4 units (2 vertical grid spaces) for 1 unit to the right (1 horizontal grid space). It seems to cross y = 1 at about x = 1/2.
x = 1/2 when y = 1.
Answer:
35:
30 (tens) 5 (ones)
16:
10 (tens) 6 (ones)
Step-by-step explanation:
Add the tens:
30+10 =40
Add the ones:
5+6=11
Add the final answer for the tens and ones together:
40+11=51
I hope this helps! Lemme know in the comments if this made sense to you?
Given the equation: (km / 3) - 2x = 4, it is essential to isolate x to obtain the expression to solve it. This is done below:
(km / 3<span>) - 2x = 4
</span>
Adding 2x to both sides:
(km / 3<span>) - 2x + 2x = 4 + 2x
</span>(km / 3<span>) = 4 + 2x
</span>
Subtracting 4 from both sides:
(km / 3<span>) - 4 = 4 + 2x - 4
</span>(km / 3<span>) - 4 = 2x
</span>
Dividing 2 from both sides:
[(km / 3<span>) - 4] /2 = 2x /2
</span>[(km / 3<span>) - 4] /2 = x
</span>x = (km / 6) - 2
