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Morgarella [4.7K]
3 years ago
8

Find the area A: 54.94 cm B: 40.59 cm C: 33.165 cm D: 27.47 cm

Mathematics
2 answers:
aleksandrvk [35]3 years ago
8 0
D: 27.47 cm. A=b×h÷2

6.7×8.2=54.94
54.94÷2=27.47 cm

hey what can I say except your welcome.
jasenka [17]3 years ago
4 0
27.47 because 8.2 and 6.7 are the base and height of the triangle and the formula for a triangle is A: B*H/2
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10 to the power of 16 times 10 to the power of -3
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Answer:

the answer is the Scientific notation of 1×10^13

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Solve by Factoring<br><br> 3b^4−6b^2+27b
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Answer:

Step-by-step explanation:

hello :

3b^4−6b^2+27b = 3b(b^3-2b+9)

8 0
3 years ago
Solve for this equation:<br> x(x+3)(x+3)=0
Marta_Voda [28]

Answer:

x^3+6x^2+9x

if you are trying to find the original function

if not, and you are trying to find the zeros is

x=-3

x=0

Step-by-step explanation:

multiply x(x+3)

x^2+3x

then multiply that by x+3 and that should give you the answer

6 0
2 years ago
Read 2 more answers
Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa
blagie [28]

Answer:

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>1.9)=0.0287  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

4 0
3 years ago
Read 2 more answers
@jdoe<br><br> As promised. The link will be whatever.
Lady_Fox [76]
Ok, so we see in
y=a(x-h)^2+k
vertex is (h,k)
vertex is highest or lowest point
on one side, it goes up and other side it goes down

if a is positive, then it goes down then up
if a is negative, it goes up then down

we see
f(x)=2(x+3)^2+2
2 is positive
goes down then up
vertex is (-3,2)

so decreases from -infinity to -3 or ininterval
(-infinity,-3)

answer is first option
6 0
3 years ago
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