As per the problem,
Rhonda bought a new laptop for $800.
The laptop depreciates, or loses, 20% of its value each year.
The value of the laptop at a later time can be found using the formula

Here we have
P=$800
r=20%=0.20
t=2 years
Substitute the values in equation (1) we get

The laptop be worth in two years will be $512.
Times it bye 4 thin subtract bye 6
Hi there! A = 78
A + 44 = B
We can plug in the values of A and B into the equation. We then get an equation with only one variable (x), which we can solve.
1x + 76 + 44 = - 6x + 134
Collect terms.
1x + 120 = - 6x + 134
Add 6x to both sides.
7x + 120 = 134
Subtract 120 from both sides
7x = 14
Divide both sides by 7
x = 14 / 7 = 2
A = 1x + 76
Now plug in the value of x we just found
A = 2 + 76 = 78
I think its supposed to be divide so i think C. would be the answer