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Leno4ka [110]
2 years ago
7

Simplify the expression. (−3)^−4

Mathematics
1 answer:
vova2212 [387]2 years ago
3 0

Answer:

1/81

Step-by-step explanation:

In the problem, we are given the expression \displaystyle \large{(-3)^{-4}}. To simplify this expression, we have to use laws of exponents since we cannot directly evaluate negative exponent by default. The law of exponent specifically for this expression is:

\displaystyle \large{a^{-n}=\dfrac{1}{a^n}}

Apply the formula to our given expression in.

\displaystyle \large{(-3)^{-4}=\dfrac{1}{(-3)^4}}

Evaluate the expression.

\displaystyle \large{(-3)^{-4}=\dfrac{1}{(-3)(-3)(-3)(-3)}}\\\\\displaystyle \large{(-3)^{-4}=\dfrac{1}{81}}

Always keep in mind that for \displaystyle \large{a^{2n}} when \displaystyle \large{a \in \mathbb{R}} and \displaystyle \large{n \in \mathbb{I} - \{0\}} the expression will always remain positive.

Please let me know if you have any questions!

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Answer:

\large\boxed{(x^2+43x+10)-(10x^2-5x+10)=-9x^2+48x}

Step-by-step explanation:

(x^2+43x+10)-(10x^2-5x+10)\\\\=x^2+43x+10-10x^2-(-5x)-10\\\\=x^2+43x+10-10x^2+5x-10\qquad\text{combine like terms}\\\\=(x^2-10x^2)+(43x+5x)+(10-10)\\\\=-9x^2+48x

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Step-by-step explanation:

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Answer:

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Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po
jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.

Step-by-step explanation:

The given equation is

x^3-21x=-20

It can be written as

x^3+0x^2-21x+20=0

Splitting the middle terms, we get

x^3-x^2+x^2-x-20x+20=0

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Splitting the middle terms, we get

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Using zero product property, we get

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Therefore, the zeroes of the equation are 1, 4 and -5.

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x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.

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