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madreJ [45]
3 years ago
14

What’s 3yrs and 4 months as a decimal?

Mathematics
1 answer:
kap26 [50]3 years ago
5 0
I think it is 3.4
3 would be the whole
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What is the LCM of 8,15,10
GaryK [48]
The LCM for 8, 15, and 10 is 120.
4 0
3 years ago
(5,12) with a slope m=10 the equation of the line is
motikmotik

Answer:

y= 10x-38

Step-by-step explanation:

Equation of a line is usually written in the form of y=mx+c, where m is its gradient and c is its y-intercept.

Given that m=10,

y= 10x +c

Now substitute the coordinates into the equation.

When y=12, x=5,

12= 10(5) +c

12= 50 +c

c= 12 -50

c= -38

Thus the equation of the line is y= 10x -38

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D
Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
Which point is a solution to y&lt;4x+5
Alla [95]

Answer:

(1,-1)

Step-by-step explanation:

y < 4x+5

x = 1, y = -1 => -1 < -4+5 (T)

3 0
3 years ago
What is the solution of log3x − 5 16 = 2?
Stolb23 [73]

Answer:

log (16)=2 in base 3x-5

==>16=2^(3x-5)

==>2^4=2^(3x-5)

==>4=3x-5

==>3x=9

==>x=3

Step-by-step explanation:

4 0
3 years ago
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