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Soloha48 [4]
3 years ago
6

A car of 1000 kg starts to move from rest and travels a distance of 150 m in 10 second. How much force is needed?​

Mathematics
1 answer:
allsm [11]3 years ago
3 0
  • Initial velocity=u=0m/s
  • Distance=s=150m
  • Time=t=10s
  • Acceleration=a

Using second equation of kinematics

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto 150=0(10)+\dfrac{1}{2}a(10)^2

\\ \sf\longmapsto 150=\dfrac{1}{2}\times 100a

\\ \sf\longmapsto 50a=150

\\ \sf\longmapsto a=\dfrac{150}{50}

\\ \sf\longmapsto a=3m/s^2

  • Mass=m=1000kg
  • Force=F

Using newtons second law

\\ \sf\longmapsto F=ma

\\ \sf\longmapsto F=1000(3)

\\ \sf\longmapsto F=3000N

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Answer:

2.06 \times 10^-^2 = 206

1.88 \times 10^-^1 = 18.8

206 \times 18.8 = 3,872.8

7.69 \times 10^-^2 = 769

2.3 \times 10^-^5  = 230,000

=\frac{769}{230000}

= 0.00334

therefore,

3,872.80 > 0.00334

Step-by-step explanation:

Which statement is correct?

(2.06x102x1.88 x 10-1) <7.69x 10

2.3x10-5

(2.06 x 10-2)(1.88 x 10-1) 7.69x 10-

2.3x10-5

7.69 x 10"

(2.06 x 10-2x1.88x10-)>

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Given that;

2.06 \times 10^-^2 = 206

1.88 \times 10^-^1 = 18.8

206 \times 18.8 = 3,872.8

7.69 \times 10^-^2 = 769

2.3 \times 10^-^5  = 230,000

=\frac{769}{230000}

= 0.00334

therefore,

3,872.80 > 0.00334

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The length of a rectangle is 4 cm less than it’s width. If the area of the rectangle is 165 cm^2. What are the dimensions of the
Monica [59]

Answer:

The dimensions are 11 cm by 15 cm

Step-by-step explanation:

Area of a rectangle = (length)(width).

Let L represent the length and W the width.

Since L = W - 4, we have

Area of rectangle = (W - 4)W = 165 cm^2.

Thus, w^2 - 4W - 165 = 0.  We can solve for W using the quadratic formula:

a = 1, b = -4 and c = -165.  Thus,

        -(-4) ± √ [ (-4)² - 4(1)(-165) ]

W = ---------------------------------------

                        2

         4 ± √ [16 + 660 ]

W = ------------------------------

                       2

         4 ± √ [ 676 ]                    4 ± 26

W = -----------------------  =   W = -------------  =  W  = 2 ± 13

                  2                                  2

Thus, W is 2 + 13 = 15.  It cannot be negative, so we discard 2 - 13 = -11.

If the width, W, is 15, then the length is 4 less, or L = 11.

The dimensions are 11 cm by 15 cm

6 0
4 years ago
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