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3 years ago

Here is the question: Alicia wrote numbers:2,9,15,21 what of the numbers is not a composite number?

Mathematics

2 answers:

Zolol [24]3 years ago

8 0

the answer is 2 because you can't divided 2 by anything else other then itself

netineya [11]3 years ago

4 0

2 bc nothing goes into 2 where the other ones have factors

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Use an area model to solve the expression 0.6 × 0.4. (6-4)

Vinvika [58]

Step-by-step explanation:

the answer is 48 because

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3 years ago

Evaluate:(0.0001)-¾

RSB [31]

Answer:

0.001

Step-by-step explanation:

(0.0001)^-3/4=((0.1)⁴)^-3/4

(0.1)^4×-3/4

0.1^‐3

0.001

8 0

3 years ago

Solve by factorising <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="abs

Paladinen [302]

Step-by-step explanation:

$\underline{ \underline{ \text{Solving \: a \: quadratic \: equation \: by \: factorisation \: method}}} :$

In this method , the second order of polynomial ax² + bx + c is factorised and expressed as the product of two linear factors. Then each linear factor is separately solved to get the required solutions of the equation by applying zero factor property. In zero factor property , if p•q = 0 , then either p = 0 or q = 0 . In other words , if the product of two numbers is 0 , then one or both of the numbers must be 0.

$\underline{ \underline{ \text{Let's \: solve}}} :$

$\tt{ {x}^{2} + 16x + 55 = 0}$

Here , we have to find the two numbers that multiplies to 55 and adds to 16.

⤑ $\tt{ {x}^{2} + (11 + 5)x + 55 = 0}$

⤑ $\tt{ {x}^{2} + 11x + 5x + 55 = 0}$

⤑ $\tt{x(x + 11) + 5(x + 11) = 0}$

⤑ $\tt{(x + 5)(x + 11) = 0}$

Either :

$\tt{x + 5 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: Or : \: \: x + 11 = 0}$

$\sf{⟶ x = 0 - 5} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:⟶ x = 0 - 11$

$\tt{⟶x = - 5 } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:⟶ x = - 11$

$\red{ \boxed{ \boxed{ { \tt{Our \: final \: answer : \boxed{ \underline{ \bold{ \tt{x = - 5 \: , - 11}}}}}}}}}$

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0

3 years ago

16. Solve for "x". a. 6 b. 100 c. 36

erastovalidia [21]

Answer:

A. 6

Step-by-step explanation:

Using the Pythagorean theorem which states that: Hypotenus² = Opposite² + Adjacent²

Where: hypotenus = 10, opposite = x, adjacent = 8

So:

${10}^{2} = {x}^{2} + {8}^{2}$

Solving for x

$100 = {x}^{2} + 64$

Collect like terms to make x the subject of formula

$100 - 64 = {x}^{2} →36 = {x}^{2}$

$36 = {x}^{2} ⟹ {x}^{2} = 36$

square root both sides of the equation to find the value of x

$\sqrt{ {x}^{2} } = \sqrt{36} →x = 6$

Therefore: Option A is correct

5 0

1 year ago

HELP PLEASE solve the right triangle

aleksandrvk [35]

Answer:

Part 1) $FG=4.4\ units$

Part 2) $EF=3.9\ units$

Part 3) $m\angle G=63^o$

Step-by-step explanation:

step 1

Find the measure of length side FG

In the right triangle EFG

we know that

$sin(27^o)=\frac{GE}{FG}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(27^o)=\frac{2}{FG}$

$FG=\frac{2}{sin(27^o)}=4.4\ units$

step 2

Find the measure of length side EF

In the right triangle EFG

we know that

$cos(27^o)=\frac{EF}{FG}$ ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

$cos(27^o)=\frac{EF}{4.4}$

$EF=cos(27^o)(4.4)=3.9\ units$

step 3

Find the measure of angle G

we know that

$m\angle G+27^o=90^o$ ---> by complementary angles in a right triangle

$m\angle G=90^o-27^o=63^o$

7 0

3 years ago