Question

13/7x^2+11x/8(x+3). The question asks to “rewrite with a common denominator and I’m not sure how

Answer 1

Answer:

$\frac{77x^{3}+104x+312}{56x^{2}(x+3)}$

Step-by-step explanation:

The original expression:

$\frac{13}{7x^{2}} + \frac{11x}{ 8(x + 3)}$

Multiply each term by the product of the denominators:

$= \frac{13\times8(x+3)}{7x^{2}\times 8(x+3)} + \frac{7x^{2}\times11x}{7x^{2}\times8(x+3)}$

Add the two fractions:

$= \frac{13\times8(x+3)+7x^{2}\times11x}{7x^{2}\times 8(x+3)}$

Combine like terms:

$= \frac{104(x+3)+77x^{3}}{56x^{2}(x+3)}$

Simplify the numerator:

$= \frac{77x^{3}+104x+312}{56x^{2}(x+3)}$