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VikaD [51]
3 years ago
15

What is the difference between type i error and type ii error?

Mathematics
1 answer:
Andrej [43]3 years ago
5 0
A type i error, as an example, is saying to a person that doesn't have ADHD, you have ADHD, or a false positive. A type ii error is saying to a person who does have ADHD, you don't have ADHD, or a false negative.

I hope this helped! :)
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Anyone know how do do this?​
Makovka662 [10]

Answer:

Step-by-step explanation:

A relation is a function if there are no shared x values.  If you look at the y-axis where x = 0, you can see that there are 2 coordinates that share that x value:

(0, -1) and (0, 3).  Because the x value in both those coordinates is the exact same number, this is NOT a function, merely a relation.  ALL functions are relations, but not all relations are functions.

The domain asks for all the included x values.  It goes from the lowest x value to the highest x value.  Our lowest x value is -4 and the function stops at an x value of 4.  So the domain is

D = {x | -4 ≤ x ≤ 4}

The range goes from the lowest y value to the highest y value.  Our lowest y value is -2 and the highest y value is 4.  So the range is

R = { y | -2 ≤ y ≤ 4}

That straight line that comes after the first x and y is the line that translates to "such that".  In words, our domain reads "x such that x is greater than or equal to -4 and less than or equal to 4" and the range reads "y such that y is greater than or equal to -2 and less than or equal to 4".

7 0
3 years ago
In another country, a road sign reads "80 kilometers to the next gas station". How far is that distance to the nearest mile?
rosijanka [135]
1 km = 0.621371 miles
80 * 0.621371 = 49.7097 miles

which is about 50
therefore your answer is B: 50 miles
3 0
3 years ago
PLZZ answer this in a simple method​
Tpy6a [65]

Answer:

hope this help you

of my handwriting is bad then sorry.

4 0
3 years ago
which of the following is a point-slope equation of a line that passes through the points (10, 5) and (4, -7)
ivolga24 [154]

\bf (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-7}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-7}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{10}}}\implies \cfrac{-12}{-6}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{2}(x-\stackrel{x_1}{10})

4 0
4 years ago
1/(5 + 3sqrt(5)) help me plzzzzz​
expeople1 [14]

Answer:

the answer is 1/(5+15sqrt)

Step-by-step explanation:

just multiply 3qrst with 5

7 0
3 years ago
Read 2 more answers
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