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Marianna [84]
1 year ago
9

Determine the type(s) of the triangle with the given coordinates. X(6,1) Y(-2,-3) Z(0,3)

Mathematics
1 answer:
jeyben [28]1 year ago
3 0

The triangle with the given coordinates X(6,1) Y(-2,-3) Z(0,3) is an isosceles triangle.

The given coordinates are X(6,1) Y(-2,-3) Z(0,3).

<h3>What are coordinates?</h3>

A coordinate system is a system in geometry that employs one or more integers, or coordinates, to define the position of points or other geometric components on a manifold, such as Euclidean space, in a unique way.

We know that, Distance formula =\sqrt{(x_{2}-x_{1}  )^{2}+(y_{2}-y_{1}  )^{2}  }

Now, XY=\sqrt{(-2-6)^{2}+(-3-1)^{2}  }=\sqrt{80} units

YZ=\sqrt{(0+2)^{2}+(3+3)^{2}  }=\sqrt{40} units

XZ=\sqrt{(0-6)^{2}+(3-1)^{2}  }=\sqrt{40} units

Here, YZ=XZ

Hence, the triangle with the given coordinates X(6,1) Y(-2,-3) Z(0,3) is an isosceles triangle.

To know more about the coordinate geometry visit:

brainly.com/question/20393391

#SPJ1

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Answer:

$8.50

Step-by-step explanation:

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Alexus [3.1K]

Answer:

a) the common difference is 20

b) x_8=115 , x_{12}=195

c) the common difference is -13

d) a_{12}=52, a_{15}=13

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: x_n=x_1+(n-1)d

We know common difference d= 20, we need to find x_1

Using x_3=16 we can find x_1

x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25

So, We have x_1 = -25

Now finding x_8

x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115

So, \mathbf{x_8=115}

Now finding x_{12}

x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195

So, \mathbf{x_{12}=195}

c) what is the common difference of the sequence a_m

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: a_n=a_1+(n-1)d

We know common difference d= -13, we need to find a_1

Using a_7=104 we can find x_1

a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195

So, We have a_1 = 195

Now finding a_{12} , put n=12

a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52

So, \mathbf{a_{12}=52}

Now finding a_{15} , put n=15

a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13

So, \mathbf{a_{15}=13}

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