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NISA [10]
3 years ago
15

Solve the equation. 11 = –d + 15 A. 4 B. 6 C. 11 D. –4

Mathematics
1 answer:
xxMikexx [17]3 years ago
8 0

11 = -d+15

subtract 15 from each side

-4 = -d

 divide both sides by -1

d = 4

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Plz somebody help. ^_^
pickupchik [31]

Answer:

sin θ =  15/17

Step-by-step explanation:

First we have to know how much the hypotenuse measures.

to take out the hypotenuse we will use pitagoras, with the following formula.

h^2 = c1^2 + c2^2

c1 = 8

c2 = 15

h^2 = 8^2 + 15^2

h^2 = 64 + 225

h = √ 289

h = 17

well to start we have to know the relationships between angles, legs and the hypotenuse.

a: adjacent

o: opposite

h: hypotenuse

sin θ = o/h

cos θ= a/h

tan θ = o/a

we want to know the sin of θ

sin θ = o/h

sin θ =  15/17

5 0
3 years ago
If it takes 10 women 8 days to make 3 treehouses, how many days does it take 6 women to make 36 treehouses
umka2103 [35]

Answer:

160 days

Step-by-step explanation:

If it takes 8 days with 10 women to make 3 tree houses, then the rate of woman per tree house is 3/80. Multiplying this by 6 and dividing by 36, you get a rate of 1/160 or 160 days. Hope this helps!

6 0
3 years ago
HELPP!!what is the answer to this picture above^
nasty-shy [4]

Answer:

\fbox{ \fbox { \sf{Distance  =  \sf{15 \: units}}}}

{ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}

Step-by-step explanation:

\star{ \:  \sf { \: Let \: the \: points \: be \: A \: and \: B}}

\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}

\underline{ \underline{ \tt{Finding \: the \: distance}}}

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(18 - 6)}^{2}  +  {(15 - 6)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(12)}^{2}  +  {(9)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{144 + 81}}}

\mapsto{ \sf{Distance =  \sqrt{225} }}

\mapsto{ \sf{Distance =  \sqrt{ {15}^{2} } }}

\mapsto{  \boxed{\sf{Distance = 15 \: units}}}

\underline{ \underline {\tt{Finding \: the \: Midpoint}}}

\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2}  \: , \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2}  \: , \:  \frac{6 + 15}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{24}{2}  \: , \:  \frac{21}{2} )}}

\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

3 0
3 years ago
In how many ways can a quality-control engineer select a sample of3 transistors for testing frm a batch of 100 transistors?
Advocard [28]

Answer:

161700 ways.

Step-by-step explanation:

The order in which the transistors are chosen is not important. This means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

3 transistors from a set of 100. So

C_{100,3} = \frac{100!}{3!(100-3)!} = 161700

So 161700 ways.

6 0
3 years ago
18.) A cylinder and a cone have the same radius and<br> the same volume. How do the heights compare?
mart [117]

Answer:

If a cone and a cylinder have the same base and the same height, then the volume of the cone is of the volume of the cylinder. For example, the cylinder and cone shown here both have a base with radius 3 feet and a height of 7 feet. The cylinder has a volume of cubic feet since .

Step-by-step explanation:

6 0
2 years ago
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