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3 years ago

Need help ASAP! Please

Mathematics

2 answers:

iren [92.7K]3 years ago

6 0

Answer:

112

Step-by-step explanation:

20 x 20 is 40

6 x 9 is 54

6 x 3 is 18

54 + 18 is 72

72 + 40 is 112

dedylja [7]3 years ago

5 0

Answer:

472

Step-by-step explanation:

Use the order of operations PEMDAS

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

9 + 3 = 12

20^2 = 400

6 * 12 = 72

400 + 72 = 472

hope this helped! :)

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. A Gardener has 6203 plants. He wants to plant this in such a way that the number of rows and the number of columns remain the

Anastasy [175]

Answer:

Step-by-step explanation:

Since he wants to have equal number of rows and columns..the number of plants must be a root number. 6203 is not a root number. 6241 is the closest root number

(√6241= 79)

So he needs a minimum of 6241 plants in total for it.

6241-6203= 38

Therefore he needs 38 more plants

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3 years ago

What is the value of n in the relationship 8n+9=-n+5

vitfil [10]

Subtract 5 from both sides.

$8n + 4 = -n$

Subtract 8n from both sides.

$4 = -9n$

Divide both sides by -9 to solve for n.

$- \frac{4}{9} = n$

The value of n is -4/9.

8 0

3 years ago

Round $99.20 to the nearest ten

Vikki [24]

Take the first 9 is in yours tens place so you want to take the second 9 and round up because anything 5 or more goes up and 4 or less stays the same

4 0

3 years ago

Read 2 more answers

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Let U = {a, b, c, e, d, e, f, g, h, i, j, k}; A = {a, b, e, f, h, j}; B = {b, c, d, f, j}. Draw a Venn Diagram with a rectangle

marishachu [46]

<h3>Answer: Venn Diagram is below</h3>

The rectangle represents the universal set (marked as "set U"). Everything is contained in this rectangle.

Circle A represents set A = {a, b, e, f, h, j}

Circle B represents set B = {b, c, d, f, j}

The common elements between the two sets are {b, f, j}, so we'll write these three values in the overlapping portion of the two circles.

The items {a,e,h} will go in circle A, but not in the overlapping portion since they are found only in set A.

Similarly we'll have {c,d} go in circle B but not in the overlapping portion since these items are only found in set B.

The remaining terms {g, i, k} go outside both circles, but inside the rectangle, because neither of these elements are in set A or set B.

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3 years ago