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Hoochie [10]
3 years ago
7

A circle has a radius of 6 meters. Find the area of the sector whose central angle is 82°. Round to the nearest tenth.

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0

The answer is 25.8 m2 if you have any questions feel free to ask

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What is the area of △JKL in square units? KJL is a triangle. The angle J is 94 degree and the angle L is 26 degree. Side JK is 2
Tamiku [17]

Answer:

426.07 square units

Step-by-step explanation:

Recall that for a triangle whose angles are A,B,C  with corresponding sides a, b, c, the area G of the triangle may be computed as

G = 1/2 ab Sin C

or

G = 1/2 bc Sin A

or

G = 1/2 ac Sin B

Going by this, recall that the sum of angles in a triangle is 180 hence

94 + 26 + K = 180

120 + K = 180

Subtract 120 from both sides

K = 180 - 120

K = 60 degrees

Given that JK = 24 and JL = 41

G = 1/2 * 24 * 41 Sin 60

= 426.07 square units

8 0
2 years ago
A 15-minute TV program consists of one commercial of 1
Margarita [4]

Answer:

6 7/8 minutes

Step-by-step explanation:

Say the entertainment segments are each x minutes long. Then, we have the equation:

x + x + 1 1/4 = 15

2x + 1 1/4 = 15

2x = 15 - 1 1/4

We need a common denominator. 1 1/4 = 5/4 and 15 = 60/4, so we now have:

60/4 - 5/4 = 55/4. Then: 2x = 55/4

Divide by 2 from both sides:

(55/4) / 2 = 55/8 = 6 7/8

Thus, each entertainment segment is 6 7/8 minutes long.

Hope this helps!

7 0
3 years ago
Read 2 more answers
If a car travels 180 km on 12 liters of gas, how many km per liter does the car get? Express in simplest form.
lora16 [44]

Answer:

<u>5 kilo-meters per liter of gas</u>

Step-by-step explanation:

180 divided by 12 would be 180 / 12 = 5 km per liter

<em>(P.S., pls mark me brainliest, and have a nice day)</em>

6 0
2 years ago
Khi m=4 cho ma trận A= -3 -2m-2 2-2m
andreev551 [17]

Answer:

AM ONLI GR 4 SORI HEHEhehe

4 0
2 years ago
Read 2 more answers
On which interval is the average rate of change for bicycle production the greatest? A) 1950 to 1960 B) 1960 to 1970 C) 1970 to
Alborosie

Answer:

D) 1980 to 2000

Step-by-step explanation:

Finding the average rate of change in each interval to determine the greatest one.

Production per interval

1950-1960 = (21-11) \ million = 10 million

1960-1970 = (41-21)\ million = 20 million

1970-1980 = (71-41)\ million = 30 million

1980-2000 = (161-71)\ million= 90 million

Rate of change (1950-1960)= \frac{10}{11} \times 100= 90.90\%

Rate of change (1960-1970) = \frac{20}{21} \times 100= 95.23\%

Rate of change (1970-1980)=  \frac{30}{41} \times 100= 73.17\%

Rate of change (1980-2000)= \frac{90}{71} \times 100= 126.76\%

∴ rate of change between 1980 to 2000 is 126.78%

7 0
2 years ago
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