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Hoochie [10]
3 years ago
7

A circle has a radius of 6 meters. Find the area of the sector whose central angle is 82°. Round to the nearest tenth.

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0

The answer is 25.8 m2 if you have any questions feel free to ask

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Julia went to 10 houses on her street for Halloween. 5 of the houses gave her a chocolate bar. What fraction of houses on Julia’
Mnenie [13.5K]

Answer:

1/2

Step-by-step explanation:

5/10 houses gave her chocolate

if you simplify 5/10 by dividing by both the top and bottom by 5 to get 1/2

3 0
3 years ago
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Answer: Buses 385

Vans 25

4 0
3 years ago
How do i solve m - 4/9 = -2 67/90
Diano4ka-milaya [45]

Answer:

m=-23/10

Step-by-step explanation:

-2 67/90=-247/90

m-4/9=-247/90

m=-247/90+4/9

m=-247/90+40/90

m=-207/90

m=-23/10

3 0
3 years ago
What is the relationship between the value of the digit 3 in 4,231 and in the value of the digit 3 in the number 3,421?
Marina CMI [18]

Answer:

A.

In 4231, the value of the digit 3 is 110 less than the value of the digit 3 in 3421.

Step-by-step explanation:

We can see that the value of 3 In 4231 is in ten while the value of 3 in 3421 is in thousands.

So to get the actual division factor, let's take 3300 and divide it by 30,

3300/30 = 110

So it's clear already, that the value of 3 in 4231 is 110 times less to the value in 3421

4 0
2 years ago
Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
3 years ago
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