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krek1111 [17]
3 years ago
6

If 2(x + 5) – (3x – 4) = 12, what is the value of x?

Mathematics
2 answers:
lozanna [386]3 years ago
5 0

Distribute: 2x + 10 - 3x + 4 = 12

Combine like-terms: -x + 14 = 12

Subtract 14 from both sides: -x = -2

Switch signs: x = 2

Ad libitum [116K]3 years ago
5 0

Answer:

The value of x will equal 2 I believe sorry if I'm wrong

Step-by-step explanation:


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Answer:

It means that you need to state whether there are any solutions and how many there are. For example if the equation ends up with an answer like 2=5 there is no solution because 2 does not equal 5. if the equation ends up with an answer of 0=0 there is infinitely many solutions because 0 does equal 0. if it comes out as x=9 there is one solution because x only has one answer to (keep in mind these are just examples)

Step-by-step explanation:

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The Pretty Pizza Company wants to open a new pizza place either on the north side of town or the south side of town. They want t
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Target: ratio of pizza places / person < 0.01

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Kevin cuts lawns during the summer months. He charges $10 plus $5 per hour. The algebraic model is C = 5h + 10, where C represen
Oxana [17]

Answer:

\begin{center}\begin{tabular}{ c c c }Hours(h) & Total Cost(C) \\ 1 & 15  \\  2 & 20  \\   3 & 25  \\ 4 & 30   \\ 5 & 35    \end{tabular}\end{center}

Step-by-step explanation:

Given that:

Kevin charges $10 plus $5 per hours

C = 5h + 10

To find:

The table of values for hours worked from 1 to 5.

Solution:

First of all, let us put h = 1 in the given equation:

C = 5 \times 1 + 10

C = 5 + 10 = $15

Now, let us put h = 2 in the given equation:

C = 5 \times 2 + 10

C = 10 + 10 = $20

Now, let us put h = 3 in the given equation:

C = 5 \times 3 + 10

C = 15 + 10 = $25

Now, let us put h = 4 in the given equation:

C = 5 \times 4 + 10

C = 20 + 10 = $30

Now, let us put h = 5 in the given equation:

C = 5 \times 5 + 10

C = 25 + 10 = $35

So, the table becomes each row incrementing h by 1:

\begin{center}\begin{tabular}{ c c c }Hours(h) & Total Cost(C) \\ 1 & 15  \\  2 & 20  \\   3 & 25  \\ 4 & 30   \\ 5 & 35    \end{tabular}\end{center}

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