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kramer
4 years ago
15

Which topology requires a central controller or hub?

Computers and Technology
1 answer:
Brut [27]4 years ago
3 0
I Think it is Topology of star but I am not sure.
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Why Prithvi Narayan Shah are appointed the person favoured by the people at Kazi
mart [117]

Answer:

At one time, Prithvi Narayan Shah could not decide who he should as the Kaji (equivalent to Prime Minister) and Pradhan Senapati (Commander-in-Chief). He had two commanders Biraj Thapa Magar and Kalu Pande in mind.

So, for the decision, he called a Bhaardaari Sabhaa (assembly of the courtiers) along with some people of his kingdom and chose Kalu Pande on the basis of popularity. He instructs his descendants in Divyopadesh to understand the popularity before nominating someone as the Kaji.

This is not a true democratic system as the candidates don't really come from between the people. The candidates are the two people who the King thinks are capable and only wants to know who is popular. This only seems like a precursor of democracy we have today.

I would not call Prithvi Narayan Shah was a democratic king, though

Explanation:

3 0
3 years ago
Jason wants to open a program with the command prompt window. Which command should he type in the Run dialog box to open the com
Montano1993 [528]
<span>1. Tap or click the Start button, followed by All apps.

If you're not using the Desktop in Windows 10, tap the All apps button on the bottom-left of your screen instead. It's the icon that looks like the small list of items.

Tip: The Power User Menu is a much faster way to get to Command Prompt in Windows 10 but only if you're using a keyboard or mouse. Just choose Command Prompt from the menu that appears after pressing WIN+X or right-clicking on the Start button. </span><span><span>Find the Windows System folder from the list of apps and tap or click it. </span><span>Under the Windows System folder, click or tap Command Prompt.

Command Prompt should open immediately. </span><span>You can now execute whatever commands in Windows 10 you'd like to run.</span></span>
4 0
3 years ago
Write a program that takes paragraph from the user and prints all unique words in that paragraph using strings in c++
Bezzdna [24]

Answer:

void printUniquedWords(char filename[])

void printUniquedWords(char filename[]) {

void printUniquedWords(char filename[]) {     // Whatever your t.text file is

    fstream fs(filename);

    fstream fs(filename);   

    fstream fs(filename);       

    fstream fs(filename);           map<string, int> mp;

    fstream fs(filename);           map<string, int> mp;   

    fstream fs(filename);           map<string, int> mp;       // This serves to keep a record of the words

    string word;

    string word;     while (fs >> word)

    string word;     while (fs >> word)     {

    string word;     while (fs >> word)     {         // Verifies if this is the first time the word appears hence "unique word"

        if (!mp.count(word))

        if (!mp.count(word))             mp.insert(make_pair(word, 1));

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }   

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();   

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)     {

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)     {         if (p->second == 1)

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)     {         if (p->second == 1)             cout << p->first << endl;

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)     {         if (p->second == 1)             cout << p->first << endl;     }

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)     {         if (p->second == 1)             cout << p->first << endl;     } }

5 0
3 years ago
What is a half note + a 8th note in band? plz helppp
skad [1K]
One quarter note plus one eighth note equals one and a half beats. So a dotted quarter note lasts for one and a half beats.
3 0
3 years ago
Read 2 more answers
Order the following routine maintenance tasks from most to least important when securing a computer. a. Verify anti-malware sett
spin [16.1K]

Answer:

The following are the order of the routine maintenance tasks that is C, A, B, D

Explanation:

For securing the computer system the user has to follow some steps related to the routine maintenance tasks.

  • Firstly, the user has to validate the settings on the Windows Update.
  • Then, they have to validate the settings on the anti-malware software.
  • Then, the user has to validate the setting related to the file-sharing system.
  • Finally, they have to validate the frequent optimization of hard drives or hard disks.
7 0
3 years ago
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