Answer:
public class Main
{
public static void main(String[] args) {
System.out.println(min(3, -2, 7));
}
public static int min(int n1, int n2, int n3){
int smallest = Math.min(Math.min(n1, n2), n3);
return smallest;
}
}
Explanation:
*The code is in Java.
Create a method named min that takes three parameters, n1, n2, and n3
Inside the method:
Call the method Math.min() to find the smallest among n1 and n2. Then, pass the result of this method to Math.min() again with n3 to find the min among three of them and return it. Note that Math.min() returns the smallest number among two parameters.
In the main:
Call the method with parameters given in the example and print the result
The statements that correctly describe the time complexity of data structures with N data are:
- The average time complexity of the data lookup in a hash table is O(N).
- The average time complexity of inserting data into a heap is O(logN)
<h3>What is time complexity of data structures?</h3>
Time Complexity of an algorithm is known to be the depiction of the amount of time needed by the algorithm to carry out to completion.
Note that The statements that correctly describe the time complexity of data structures with N data are:
- The average time complexity of the data lookup in a hash table is O(N).
- The average time complexity of inserting data into a heap is O(logN)
Learn more about data from
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Answer:
Data Mining.
Explanation:
Data Mining is the process in which a computer software uses database technology,artificial intelligence and statistical analysis so that it can find the hidden patterns,connections and trends in the data.To help business owners to make better marketing decisions and predictions about the customer's behavior.
Answer:
888 + 88 + 8 + 8 + 8 = 1000
Explanation:
Required
Add up to 1000 using only digit 8
There is no straight way to answer this question; so, we make use of trial by error method to arrive at our solution.
After several trials, I found out that:
888 + 88 + 8 + 8 + 8 = 1000
Answer:
inFile.open("progdata.dat");
Explanation:
This command opens the file which is passed to it as an argument. We are quite used to the C++'s cin and cout functions contained in iostream library for reading and writing data, however, when working will real-life stuff, we find ourselves working with huge data saved as separate files and require our programs to read them, manipulate them and possibly write back to the files... The first operation usually carried out before a file can be read or written to is open