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FromTheMoon [43]

4 years ago

11

Find f(0) and f(2) for the given exponential function. f(x) = (1/2)^-x

1 answer:

Aliun [14]4 years ago

8 0

For 0 it will equal 1 because anything to the 0th power is 1 except 0 to the 0.

For 2, It will equal for because when you raise a fraction to the negative power you flip it and that gets rid of the negative number so then you will have 2 to the second and you will get 4.

f (0) = 1, f (2) = 4

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What is the standard form equation of an ellipse that has vertices (−2,14) and (−2,−12) and co-vertices (9,1) and (−13,1)?

Gennadij [26K]

Answer:

$\frac{(x+2)^2}{121} + \frac{(y-1)^2}{169} = 1$

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First, we identify that the vertices are vertical.
(an image below is attached if you want to see a visualization)
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Sonja [21]

Answer:

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Given

$4.8xy+36y^2+0.16x^2$

Required

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$0.16x^2+4.8xy+36y^2$

Expand

$0.16x^2 + 2.4xy + 2.4xy + 36y^2$

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$0.4x(0.4x + 6y) + 6y(0.4x + 6y)$

Factor out 0.4x + 6y

$(0.4x + 6y)(0.4x + 6y)$

Express as a square:

$(0.4x + 6y)^2$

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3 years ago