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Alexus [3.1K]
3 years ago
7

Write as a square of a binomial: 4.8xy+36y^2+0.16 i will give brainliest plz solve

Mathematics
1 answer:
Sonja [21]3 years ago
5 0

Answer:

(0.4x + 6y)^2

Step-by-step explanation:

Given

4.8xy+36y^2+0.16x^2

Required

Express as a binomial squared

4.8xy+36y^2+0.16x^2

Rewrite as:

0.16x^2+4.8xy+36y^2

Expand

0.16x^2 + 2.4xy + 2.4xy + 36y^2

Factorize:

0.4x(0.4x + 6y) + 6y(0.4x + 6y)

Factor out 0.4x + 6y

(0.4x + 6y)(0.4x + 6y)

Express as a square:

(0.4x + 6y)^2

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A state offers two lottery games, WinOne and PlayBall. Both games cost $2 per ticket.
uysha [10]
In this question, both tickets cost 2$ per ticket.
The answer to this question would be: $0

In WinOne scenario, you need to match a ticket that has to pick from A-J(10 possibilities) and 0-9 (10 possibilities). The chance to win would be: 1/10* 1/10= 1/100

The expected value must be:
E= chance to win * win amount - ticket price
E= 1//100*$200 - $2= $2-$2= 0
8 0
3 years ago
35% of the spectators at a baseball match are New York Yankees fan and the rest are Boston Red Sox fan. 30% of the fans in both
Ilya [14]

Answer:

Step-by-step explanation:

At a Baseball Match.

35% of spectators are New York Yankees fan

The rest are Boston Red Sox fan = 100 - 35% = 65%

30% of fans in both teams are females.

30% of 35% of spectators are New York Yankees fan = 0.105 females

30% of 65% of spectators are Boston Red Sox fan = 0.195 females

The number of males in New York Yankees fan = 1 - 0.105 females

= 0.895 males

The number of males in Boston Red Sox fan = 1 - 0.195 females

= 0.805 males

7 0
3 years ago
This year the CDC reported that 30% of adults received their flu shot. Of those adults who received their flu shot,
Vlad [161]

Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Person has the flu.
  • Event B: Person got the flu shot.

The percentages associated with getting the flu are:

  • 20% of 30%(got the shot).
  • 65% of 70%(did not get the shot).

Hence:

P(A) = 0.2(0.3) + 0.65(0.7) = 0.515

The probability of both having the flu and getting the shot is:

P(A \cap B) = 0.2(0.3) = 0.06

Hence, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.515} = 0.1165

0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

To learn more about conditional probability, you can take a look at brainly.com/question/14398287

7 0
2 years ago
Please help!
wariber [46]
Ya is = 10x-28 see the picture for explanation
5 0
2 years ago
Write the equation 7x + 8y =4 in the form y = mx + b. (2 points)
Veseljchak [2.6K]

Answer:

it's your first answer of

y= (-7/8)x + 1/2

8 0
3 years ago
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