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madreJ [45]
3 years ago
11

Can you solve the equation 2/3(4x - 5)= 8 by using the division property of equality? explain.

Mathematics
1 answer:
bija089 [108]3 years ago
8 0

\dfrac{2}{3}(4x-5)=8\qquad|\text{use the division property of equality}\\\\\dfrac{2}{3}(4x-5):\dfrac{2}{3}=8:\dfrac{2}{3}\\\\\dfrac{2}{3}(4x-5)\cdot\dfrac{3}{2}=8\cdot\dfrac{3}{2}\\\\4x-5=4\cdot3\\\\4x-5=12\qquad|\text{use addition property of equality}\\\\4x-5+5=12+5\\\\4x=17\qquad|\text{use the division property of equality}\\\\4x : 4=17:4\\\\x=\dfrac{17}{4}

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ycow [4]

Answer:

3 or 6/2

Step-by-step explanation:

when there are two subtraction signs it can be taken as a plus sign

1/2 + 5/2

1/2 + 5/2 = 6/2

6 / 2 = 3

3 is your answer

4 0
2 years ago
Suppose you know the perimeter of n octagons arranged as shown. What would you do to find the perimeter if 1 more octagon was ad
kogti [31]

As shown in the figures given :

For Figure 1 : perimeter = 8 units   [As can be seen in the figure]

For figure 2(with 2 octagons) : perimeter = 8 × 2 - 1 = 15 units    [since 1 side is common ]

For figure 2(with 3 octagons) : perimeter = 8 × 3 - 2 = 22 units  [since 2 sides is common ]

If one more octagon is added

then perimeter = 8 × 4 - 3 = 29 units    [since 3 sides will be common ]


3 0
3 years ago
If the weight of a class 4 truck is increased by two tons will it still be classified as a class 4 truck
Assoli18 [71]
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8 0
3 years ago
Name the property of multiplication that is showing by the equation 4x*1=4x
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3 0
3 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
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