Question

If f (x) = StartRoot one-half x minus 10 EndRoot + 3, which inequality can be used to find the domain of f(x)?

Answer 1

$\left(\frac{1}{2}\right) x-10+3 \geq 0$ is the inequality that can be used to find the domain of given f(x).

Step-by-step explanation:

For a square root function given by $f(x)=\sqrt{a(x)}$, to have real values, the radicand x must be positive or equal to zero. So, domain for f(x) would be,

                 $a x \geq 0$

Given:

               $f(x)=\sqrt{\left(\frac{1}{2}\right) x-10}+3$

In the given expression, under the square root, in place of ‘x’ presents as below and so

             $\left(\frac{1}{2}\right) x-10+3 \geq 0$

The inequality depends on the true form of the given term,  so it should be,

             $\left(\frac{1}{2}\right) x-10+3 \geq 0$

Answer 2

Answer:

the answer is C

Step-by-step explanation:

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