Answer: C. Industrialization created factory jobs in urban areas while eliminating agricultural jobs in rural areas.
Explanation:
In the late 19th century, industrialization was in full swing and technology was being created that made farming more efficient. This led to a loss of jobs for people in the rural areas who depended mostly on farming.
These people then had to move to urban areas where industrialization had led to the construction of factories that required more labor. This significantly increased rural to urban migration.
Answer:
1.6 jumps/seconds.
Explanation:
Given the following data;
Total number of jumps = 144 jumps
Time = 90 seconds
To find the average jump rate;

Substituting into the formula, we have;

Average jump rate = 1.5555 ≈ 1.6 jumps/seconds.
Answer:
The width of the bigger phone is 2.99 in
Explanation:
Given



See attachment for the measure of cell phones
Required
Determine the width of the bigger version (L2)
To do this, we make use of the following equivalent ratios.

This gives:

Express as fractions


Make W2 the subject



The minerals comprising the rock can be identified using common field testing methods for individual minerals, particularly where the texture is sufficiently coarse-grained enough to distinguish the individual minerals with the naked eye or a hand lens.