Compute the necessary values/derivatives of
at
:






Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial)
at
by


###
Another way of doing this would be to solve for the coefficients
in

by expanding the right hand side and matching up terms with the same power of
.
You just have to set the denominator to zero and solve for x
S = Speed
D = Distance
T = Time
S = D/T
S = 50m/1/2
50 divided by 1/2 = 25
25 = 50/1/2
S = 25 m/min.
Answer:
The quotient is 48.
Step-by-step explanation:
Estimate the quotient using compatible numbers:
45 (or I guess any number close the answer above, not sure tbh)
Multiply the estimate by 21:
945
45*21
Is the estimate to high or too low?
too low
Adjust and continue until the product is 1008.
1008/21=48
Have a good day/evening! I hope my answer is correct!
For the more amount of the time the larger it will grow.