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gtnhenbr [62]
3 years ago
3

Which equation represents a line that passes through (5, 1) and has a slope of StartFraction one-half EndFraction?

Mathematics
1 answer:
sesenic [268]3 years ago
5 0

Answer:

y - 1 = 1/2(x -5)

Just took the test, hope this helps!

XxMandy_WolfxX
3 years ago
thank you
Maddie_Bervig
3 years ago
thanks!
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Find an equation of a line through (0, -7) and parallel to the line y=1/2x+5.
marysya [2.9K]

Answer:

The answer to your question is y = 1/2x - 7

Step-by-step explanation:

Data

Point = (0, -7)

line = y = 1/2x + 5

Parallel line have the same slope.

Slope of the first line = 1/2

Slope of the new line = 1/2

Equation of the line

                y - y1 = m(x - x1)

Substitution

                 y + 7 = 1/2(x + 0)

Simplification

                 y + 7 = 1/2x

result

                 y = 1/2x - 7

         

5 0
4 years ago
Find the ratio as simply as possible in the form a : b.
Charra [1.4K]
<h2>>> Answer </h2>

_________

\:

3 \frac{1}{2}  : 1 \frac{1}{7}

=  \frac{3 \frac{1}{2} }{1 \frac{1}{7} }

=  \frac{ \frac{7}{2} }{ \frac{8}{7} }

=  \frac{7}{2}  \times  \frac{7}{8}

=  \frac{49}{16}

= 49  : 16

7 0
3 years ago
Question 8 of 10
AleksandrR [38]
B. A worker with 40 hours of training is paid $1700 per month.
4 0
3 years ago
12 x 3.4x - 5.4x - x
icang [17]

Answer:

34.4x

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.75241,0.06281)  

Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 -2*0.06281 =5.6121

And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 +2*0.06281 =5.8886

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

5 0
3 years ago
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