FInd three consecutive integers such that twice the greatest integer is 6 less than 3 times the least integers. What are they?
2 answers:
<span>x=least of three consecutive integers
x+1=2nd of three consecutive integers
x+2=greatest of three consecutive integers
2(x+2)=3x-6
2x+4=3x-6
x=10
x+1=11
x+2=12
three consecutive integers: 10, 11, 12
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<em />I hope this is correct!
</span>
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The answer is D
Hope this helps
Answer:
20 Outcomes.
Step-by-step explanation:
A-1 A-2 A-3 A-4
B-1 B-2 B-3 B-4
C-1 C-2 C-3 C-4
D-1 D-2 D-3 D-4
E-1 E-2 E-3 E-4
Hope this helps!
93 x 10^6 =
93 x 1,000,000 = 93,000,000
Answer:
25.8
258.
2580.
Step-by-step explanation:
just move the decimal that many times
