FInd three consecutive integers such that twice the greatest integer is 6 less than 3 times the least integers. What are they?
2 answers:
<span>x=least of three consecutive integers
x+1=2nd of three consecutive integers
x+2=greatest of three consecutive integers
2(x+2)=3x-6
2x+4=3x-6
x=10
x+1=11
x+2=12
three consecutive integers: 10, 11, 12
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<em />I hope this is correct!
</span>
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