There’s not actually a question. But I might be able to help if u show the full problem
Answer:
TU ≈ 12.96
Step-by-step explanation:
Using the Altitude on Hypotenuse theorem
(leg of outer triangle)² = (part of hypotenuse below it) × (whole hypotenuse)
TU² = UV × SU = 6 × 28 = 168 ( take square root of both sides )
TU = 
≈ 12.96 ( to the nearest hundredth )
This work is faster rate than grading 36 assignments in 30 minutes because :
25 ÷ 20 = 1.25
1.25 hw assignment per minute
36 ÷ 30 = 1.2
1.2 hw assignments per minute
Answer:
26 ft and 46 ft.
Step-by-step explanation:
The prime factors of 42 are 2 * 3 * 7.
Possible lengths and widths are:
L = 7, W = 6 giving a perimeter of 2*7 + 2*6 = 26 ft.
L = 14 , W = 3 giving perimeter = 34 ft.
L = 21, W = 2 giving perimeter = 46 ft.
Ln 54.598... = 4 because ln = log e
