To find the superficial area of a prism you have to do base perimeter * height
So find the perimeter of the right triangle: 9+8+5 = 22 yd
Then find the superficial area 22*12 = 264 yd^2
Answer:
(
3
x
−
2
)
(
x
−
2
)
=
0
Set 3
x
−
2 equal to 0 and solve for x
.
x
=
2
3
Set x
−
2 equal to 0 and solve for x
.
x
=
2
The solution is the result of 3
x
−
2
=
0 and x
−
2
=
0.
x
=
2
3
,
2
The result can be shown in multiple forms.
Exact Form:
x
=
2
3
,
2
Decimal Form:
x
=
0.
¯
6,
2
Step-by-step explanation: There you go hope it helps
D
using the double - angle identity
cos (2A) = cos² A - sin² A = 2cos² A - 1 = 1 - 2sin² A
the right side = 1 - 2sin² (112.5° ) with A = 22.5°
hence 2A = 2 × 22.5° = 45°
thus cos 45° = 1 - 2sin² ( 22.5°)
You solve the equation : t^2 - 9t - 90 = 0 ;
Δ = ( - 9 )^2 - 4 * 1 * ( - 90 ) = 81 + 360 = 441 ;
t1 = ( 9 +
) / 2 = 30 / 2 = 15 ;
t2 = ( 9 -
) / 2 = -12 / 2 = - 6 ;
The numbers are 15 and - 6 ;
C, because 12 squared plus 16 squared equals 544, then you take the square root of
