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AveGali [126]
2 years ago
6

Seven less than twice a number is 13

Mathematics
1 answer:
frozen [14]2 years ago
6 0

Answer:

the answer is -5

Step-by-step explanation: hope this helps :)

pls mark brainliest

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Find the mean and range.<br><br> 26 19 23 39 31 34 23 25
sveticcg [70]
Range: largest number minus the smallest number
39 - 19 = 20
your range is 20

Mean: add all of the numbers and divide by the amount of numbers there are.

26+19+23+39+31+34+23+25= 220
220/8 = 27.5

your mean is 27.5

hope this helps
7 0
3 years ago
Read 2 more answers
The number of points in the first five games of the basketball season are listed below. What is the mean number of points scored
Fudgin [204]

Answer: 29

Step-by-step explanation:

7 0
3 years ago
Find the volume V or height H of the cylinder. Round your answer to the nearest tenth
andrew-mc [135]
X = multiplication
h = height
r^2 = radius squared

Formula of a cylinder: Pi x r^2 x height

So, if 176 = 3.14... times 4^2  times h
Then, 176 = 3.14 times 16h 
Next, 176 = 50.24h
Finally, 3.5 = h

You can then check your work by plugging 3.5 back in for the missing height and round to the nearest tenth. :) The answer should come out the same if done correctly.
8 0
3 years ago
Write a standard form of a quadratic equation that has roots - 5/2 and 3.
lora16 [44]

Answer:

2x^2 - x - 15 = 0.

Step-by-step explanation:

In factor form this is

(x + 5/2)(x - 3) = 0

x^2 + 5/2x - 3x  - 15/2 = 0

x^2 - 1/2x - 15/2 = 0

Multiply through by 2:

2x^2 - x - 15 = 0.

6 0
3 years ago
Help me answer these questions please 15, 19 and 20 please​
SpyIntel [72]

Answer:

15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

Step-by-step explanation:

We are to find the derivative of the questions pointed out.

15) K(t) = 5(5^(t)) - 2(3^(t))

Using implicit differentiation, we have;

K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P(w) = 2e^(w) - (2^(w))/5

P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)

Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)

Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

7 0
3 years ago
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