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natta225 [31]
3 years ago
15

Write a variable expression for the # of calories in e eggs and one slice of bread

Mathematics
1 answer:
miv72 [106K]3 years ago
3 0
Hmmm.... i would help but im confused with this one ahhh i need help with my hw right now but idk what the answer are ugh

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Find the volume and surface area of the square pyramid
Montano1993 [528]

The volume and surface area of the pyramid will be 392 / 3 cubic units and 189 square units. Then the correct option is A.

The complete question is attached below.

<h3>What is the volume and surface area of the pyramid? </h3>

Suppose the base of the pyramid has length = L units, width = W units, slant height = K units, and the height of the pyramid is of H units.

Then the volume of the pyramid will be

V = (L × B × H) / 3

The surface area of the pyramid will be

SA = 2(1/2 × B × K) + 2(1/2 × L × K) + (L × B)

Then the volume will be

V = (7 × 7 × 8) / 3

V = 392/3 cubic units

Then the surface area will be

SA = 2(1/2 × 7 × 10) + 2(1/2 × 7 × 10) + (7 × 7)

SA = 189 square units

Then the correct option is A.

More about the volume and surface area of the pyramid link is given below.

brainly.com/question/23302816

#SPJ1

4 0
2 years ago
Solve for x. x+2/3=−1/6
Sphinxa [80]

Answer:-

x=-5/2

Step-by-step explanation:

x+2/3=-1/6

after cross-mutiplying,

6(x+2)=-3

6x+12=-3

6x=-3-12

6x=-15

x=-15/6

x=-5/2

hope this helps u!!

6 0
3 years ago
Read 2 more answers
AB = 5x -9; BC= -2x + 12
BaLLatris [955]

Answer:

X=-3

Step-by-step explanation:

5x - 9

-2x + 12

(+) (-)

7x = -21

X= -3

plz mark ice bear as Brainliest

3 0
3 years ago
Given f(x) = 2x – 3, find the x value such that f(x) = 8.
jok3333 [9.3K]

Answer: 5.5

Step-by-step explanation:

Plugging it into the formula, we get

2x-3 = 8

Add 3 to both sides:

2x = 11

Divide by 2 on both sides:

x = 5.5

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!!!!!!!!
vitfil [10]
<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

8 0
1 year ago
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