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4 years ago

What is 2.26 (6 repeating) as a fraction?

Mathematics

1 answer:

Gekata [30.6K]4 years ago

3 0

Answer:

34/15

Step-by-step explanation:

I recognized the form of this decimal as a number divided by 3. However, when I multiplied it by 3, I got 6.8. This means that the fraction was not fully simplified. Multiplying by 5, I got 34. Since I had to multiply by 3 and then by 5 to get there, I multiplied by a total of 15. Hope this helps!

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3 years ago

4 friends are eating personal pan pizzas. Jane has 3/4, Jill had 3/4, Cindy has 2/3 left and Jeff has 2/5 left. Who has the most

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3 years ago

The midpoint of ab is m(5-2). If the coordinates of a are (6,-5), what are the coordinates of b

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3 years ago

Need help on 15 and 16 PLEASEE!!!

melisa1 [442]

Answer:

Part 15) The next three terms are 5/8,3/4 and 7/8

Part 16) The 37th term is -35.5

Step-by-step explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant and this constant is called the common difference (d)

Part 15) Find the next three terms of the arithmetic sequence

$\frac{1}{8},\frac{1}{4},\frac{3}{8},\frac{1}{2},...$

$a1=1/8\\ a2=1/4\\ a3=3/8\\ a4=1/2\\ a2-a1=1/4-1/8=1/8\\ a3-a2=3/8-1/4=1/8\\ a4=a3=1/2-3/8=1/8$

The common difference is equal to

d=1/8

Find the next three terms of the arithmetic sequence

Find a5

$a5=a4+d$ -----> $a5=1/2+1/8=5/8$

Find a6

$a6=a5+d$ -----> $a6=5/8+1/8=3/4$

Find a7

$a7=a6+d$ -----> $a7=3/4+1/8=7/8$

therefore

The next three terms are

5/8,3/4 and 7/8

Part 16) what is the 37th term of the arithmetic sequence

$4.1,3,1.9,0.8,...?$

$a1=4.1\\ a2=3\\ a3=1.9\\ a4=0.8$

$a2-a1=3-4.1=-1.1\\ a3-a2=1.9-3=-1.1\\ a4=a3=0.8-1.9=-1.1$

The common difference is equal to

d=-1.1

We can write an Arithmetic Sequence as a rule

$an=a1+d(n-1)$

substitute the values

$an=4.1-1.1(n-1)$

For n=37

substitute

$a37=4.1-1.1(37-1)$

$a37=4.1-1.1(36)$

$a37=-35.5$

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3 years ago

a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

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Answer:

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