Answer:
10
-1
1
2
Step-by-step explanation:
f(3) this one we use the second question (because the value that x is equal to is between 0 and 4)
3²+1=10
f(6) = -1 because this value is greater than 4
because the second equation has 0 inclusive we use this one for f(0)
0²+1=1
F(-3) for this one the answer is just two because x is less than 0
A = 1/2bh
Divide h by both sides.
A/h = 1/2b
Divide 1/2 by both sides.
b = 2a/h
Do you want a general solution or from 0 <= x < 2pi?
tan^2(2x) - 1 = 0
tan^2(2x) = 1
Take the square root of both sides,
tan(2x) = +/- 1
Two equations:
tan(2x) = 1
tan(2x) = -1
Solve each equation.
tan(2x) = 1, 2x = {pi/4, 5pi/4, 9pi/4, 13pi/4},
x = { pi/8, 5pi/8, 9pi/8, 13pi/8 }
tan(2x) = -1, 2x = { 3pi/4, 7pi/4, 11pi/4, 15pi/4 },
x = { 3pi/8, 7pi/8, 11pi/8, 15pi/8}
So for solutions within [0, 2pi),
x = {pi/8, 3pi/8, 5pi/8, 7pi/8, 9pi/8, 11pi/8, 13pi/8, 15pi/8 }
3.14*r^2
Hope it helps you figure them out