Hope this helps And here is the answer for you
If electrons move away from 'A', then 'A' becomes less negatively (or more positively) charged than it was originally.
If electrons move onto 'B', then 'B' becomes more negatively (or less positively) charged than it was originally.
Answer:
D(11) = 37.660 m
dD/dt = 2.7260 m/s
Explanation:
given data
two path apart = 17 m
walks east one path = 4 km/h = 1.111 m/s
walks west other path = 7 km/h = 1.944 m/s
pass each other time t = 0
solution
we consider here east is the positive direction and west is the negative direction
so that
the east - west distance between them is = 1.111 + 1.944 = 3.055 m/s
and
the actual distance between them time t is
D(t) =
at time 11 s
D(11) =
D(11) = 37.660 m
and
increase rate is dD/dt
dD/dt =
so for 11 sec
dD/dt =
dD/dt = 2.7260 m/s
Answer:
Explanation:
Electric field due to long line charge on position of charge at x = 4 m is given as
so we have
now we have
Now electric field due to the charge present at y = 2.0 m
Now total electric field is given as