It holds A. Less water than when it is warmer.
The 3rd Quadrant is the lower left one on a graph,
where ' x ' and ' y ' are both negative.
Your picture is completely unrelated to this question.
F=ma
a=F/m
F=+250N + (-130N)=120N LEFT
('m summing my forces because they are moving about the same axis, and the negative/positive accounts for the arbitrary directions I assign)
m=32kg
F=120N/32kg=3.75m/s^2 to the LEFT
3.75m/s^2 to the LEFT