1) 6 degrees per second ( you can convert it from degrees it that's not what you're looking for)
2) .47 cm per sec
Answer:
36 W
Explanation:
Power = work / time
Work = force × distance
P = F d / t
P = (72 N) (1.0 m) / (2.0 s)
P = 36 W
as we know tha momentum is product of mass and velocityi.e p=mv but here in this question velocity changes from 5m/s to 20 m/s so here formula becomes
p=(final velocity -initial velocity )mass
so (20-5)6=90kgm/s ANS
Answer:
Total energy will be ![41.6MJ](https://tex.z-dn.net/?f=41.6MJ)
Which is not in the given option
Explanation:
We have given mass m = 1 kg
Height h = 200 km = 200000 m
Speed ![v=8.9km/sec=8900 m/sec](https://tex.z-dn.net/?f=v%3D8.9km%2Fsec%3D8900%20m%2Fsec)
Acceleration due to gravity ![g=9.8m/sec^2](https://tex.z-dn.net/?f=g%3D9.8m%2Fsec%5E2)
We have to find the energy
Total energy will be sum of kinetic energy and potential energy
So ![E=\frac{1}{2}mv^2+mgh=\frac{1}{2}\times 1\times 8900^2+1\times 9.8\times 200000=3.96\times 10^11+1960000=41.6\times 10^6J=41.6MJ](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%2Bmgh%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%201%5Ctimes%208900%5E2%2B1%5Ctimes%209.8%5Ctimes%20200000%3D3.96%5Ctimes%2010%5E11%2B1960000%3D41.6%5Ctimes%2010%5E6J%3D41.6MJ)
Which is not in the given option
Answer
given,
mass of car = 800 kg
mass of truck = 1900 kg
force acting = 4900 N
a) F = (m₁+ m₂ ) a
![a = \dfrac{F}{m_1+m_2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7BF%7D%7Bm_1%2Bm_2%7D)
![a = \dfrac{4900}{800+1900}](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7B4900%7D%7B800%2B1900%7D)
a = 1.815 m/s²
a) force exerted by the car on the truck
![F = m_{truck}\times a](https://tex.z-dn.net/?f=F%20%3D%20m_%7Btruck%7D%5Ctimes%20a)
![F = 1900\times 1.815](https://tex.z-dn.net/?f=F%20%3D%201900%5Ctimes%201.815)
F = 3448.5 N
b) According to newtons third law
Force exerted by the truck on the car will be same.
Force of the truck on the car = F = 3448.5 N