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Semenov [28]
3 years ago
12

Solve for x to the tenth: 9=0.13x

Mathematics
1 answer:
Nuetrik [128]3 years ago
5 0

Answer:

69.2

Step-by-step explanation:

divide side by 0.13 to get x by itself and you end up with:

69.2307

rounding to the tenth

69.2

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En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que
Ipatiy [6.2K]

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

h_1 = Altura del frasco corto

h_2 = La altura del frasco alto es el doble que el del frasco corto. = 2h_1

d_1 = Diámetro del frasco corto

d_2 = El diámetro del frasco alto es la mitad del frasco corto = \dfrac{1}{2}d_1

El volumen de un cilindro es \pi \dfrac{d^2}{4}h

La razón de los volúmenes de los frascos es

\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2

El costo del frasco corto por unidad de volumen es

\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}

El costo del frasco alto por unidad de volumen es

\dfrac{4500}{V_2}=\dfrac{4500}{V_2}

\dfrac{4000}{V_2}

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=find%20%5C%3A%20%20%5Cfrac%7Bx%7D%7By%7D%20" id="TexFormula1" title="find \: \frac{x}{y} " al
Aliun [14]

Answer:

The Answer is: x / y = 8 / 3

Step-by-step explanation:

3(x - 2) - 4(2y - 1) + 2=0

3x - 6 - 8y + 4 + 2 = 0

3x - 8y = 0

3x = 8y

3x/y = 8

x / y = 8 / 3

Hope this Helps! Have an Awesome Day!! (-:

8 0
3 years ago
Read 2 more answers
In triangle NML, NL=NM, and the perimeter is 52 cm. A,B, and C are points of tangency to the circle. MC=6 cm. Find NL. Explain r
Natalka [10]
I hope this helps you

7 0
4 years ago
Don't mind this.......
DIA [1.3K]

Answer:

okay thank you for free points

4 0
3 years ago
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I need help with this
Softa [21]
Nothing can be done with this question!
8 0
4 years ago
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